Question

2.若复数z满足方程z²+2=0，则z³=

A.    B.     C.±2i       D.+2

Answer 1

C

      

解析：设z=a+bi

则  z²+2=0

(a+bi)²+2=0

a²+2abi-b²+2=0

            

            

∴z=±i

∴z³=(±i)³=±2i