题目内容

1.若矩阵$(\begin{array}{l}{{a}_{11}}&{{a}_{12}}\\{{a}_{21}}&{{a}_{22}}\end{array})$满足:a11,a12,a21,a22∈{0,1},且$|\begin{array}{l}{{a}_{11}}&{{a}_{12}}\\{{a}_{21}}&{{a}_{22}}\end{array}|$=0,则这样的互不相等的矩阵共有(  )
A.2个B.6个C.8个D.10个

分析 根据题意,分类讨论,考虑全为0;全为1;三个0,一个1;两个0,两个1,即可得出结论.

解答 解:由 $|\begin{array}{l}{{a}_{11}}&{{a}_{12}}\\{{a}_{21}}&{{a}_{22}}\end{array}|$=0,
可得a11a22-a12a21=0,
由于a11,a12,a21,a22∈{0,1},
可得矩阵$(\begin{array}{l}{{a}_{11}}&{{a}_{12}}\\{{a}_{21}}&{{a}_{22}}\end{array})$可以是$(\begin{array}{l}{0}&{0}\\{0}&{0}\end{array})$,$(\begin{array}{l}{1}&{1}\\{1}&{1}\end{array})$,$(\begin{array}{l}{0}&{0}\\{0}&{1}\end{array})$,$(\begin{array}{l}{1}&{0}\\{0}&{0}\end{array})$,
$(\begin{array}{l}{0}&{1}\\{0}&{0}\end{array})$,$(\begin{array}{l}{0}&{0}\\{0}&{1}\end{array})$,$(\begin{array}{l}{0}&{1}\\{0}&{1}\end{array})$,$(\begin{array}{l}{1}&{1}\\{0}&{0}\end{array})$,$(\begin{array}{l}{1}&{0}\\{1}&{0}\end{array})$,$(\begin{array}{l}{0}&{0}\\{1}&{1}\end{array})$.
则这样的互不相等的矩阵共有10个.
故选:D.

点评 本题考查二阶矩阵,解题的关键是利用二阶矩阵的含义,属于基础题.

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