题目内容
| AB |
| a |
| AC |
| b |
| AD |
| c |
| a |
| b |
| c |
| AG |
考点:共线向量与共面向量
专题:空间向量及应用
分析:利用向量的三角形法则、平行四边形法则、三角形的重心性质即可得出.
解答:
解:∵
=
+
,
=
,
=
-
,
=
(
+
),
∴
=
+
=
+
=
+
×(
-
)
=
+
=
+
+
×
(
+
)=
(
+
+
).
即
=
(
+
+
).
| AG |
| AD |
| DG |
| DG |
| 2 |
| 3 |
| DM |
| DM |
| AM |
| AD |
| AM |
| 1 |
| 2 |
| AB |
| AC |
∴
| AG |
| AD |
| DG |
| AD |
| 2 |
| 3 |
| DM |
| AD |
| 2 |
| 3 |
| AM |
| AD |
=
| 1 |
| 3 |
| AD |
| 2 |
| 3 |
| AM |
| 1 |
| 3 |
| AD |
| 2 |
| 3 |
| AD |
| 2 |
| 3 |
| 1 |
| 2 |
| AB |
| AC |
| 1 |
| 3 |
| a |
| b |
| c |
即
| AG |
| 1 |
| 3 |
| a |
| b |
| c |
点评:本题考查了向量的三角形法则、平行四边形法则、三角形的重心性质,属于基础题.
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