题目内容
计算
(1)
-
+(2
)-0.5-
π0
(2)log318-log32-log29•log34+2log23.
(1)
| (2-e)2 |
| 3 | e
| ||||
| 7 |
| 9 |
| 3 |
| 5 |
(2)log318-log32-log29•log34+2log23.
(1)原式=|2-e|-
+[(
)2]-
-
=e-2-
+(
)-1-
=e-2-e+
-
=-2.
(2)原式=log3
-
×
+3
=log332-4+3
=2-4+3
=1.
| 3 | e
| ||||
| 5 |
| 3 |
| 1 |
| 2 |
| 3 |
| 5 |
=e-2-
| 3 | e3 |
| 5 |
| 3 |
| 3 |
| 5 |
=e-2-e+
| 3 |
| 5 |
| 3 |
| 5 |
=-2.
(2)原式=log3
| 18 |
| 2 |
| 2lg3 |
| lg2 |
| 2lg2 |
| lg3 |
=log332-4+3
=2-4+3
=1.
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