题目内容

某人抛掷一枚硬币,出现正,反面的概率都是,构造数列{an},使得当第n次出现正面时,当第n次出现反面时,记Sn=a1+a2+…+an(nN*).?

(1)求S4=2的概率;

(2)记ξ=|S6|,求ξ的概率分布及数学期望.

解:(1)S4=2,需4次中有3次正面,1次反面,设其概率为P1,?

P1=C34()3·=4()4=.                                                                                ?

(2)ξ∈{0,2,4,6},                                                                                         ?

P(ξ=0)=C36()3()3=.                                                                               ?

P(ξ=2)=C46()2()4+C26()4()2=.                                                               ?

P(ξ=4)=C56()5+C16()5()=.                                                                    ?

P(ξ=6)=C66()6×2=.                                                                                         ?

E(ξ)=0×+2×+4×+6×=.      


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