题目内容
已知
=(1,1),
=(-1,2),以
,
为边作平行四边形OACB,则
与
的夹角为______.
| OA |
| OB |
| OA |
| OB |
| OC |
| AB |
∵OACB为平行四边形,
∴
| OC |
| OA |
| AC |
| OA |
| OB |
| AB |
| OB |
| OA |
∴cos<
| OC |
| AB |
| ||||
|
|
| 0×(-2)+3×1 | ||||
|
| ||
| 5 |
即
| OC |
| AB |
| ||
| 5 |
故答案为:arccos
| ||
| 5 |
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题目内容
| OA |
| OB |
| OA |
| OB |
| OC |
| AB |
| OC |
| OA |
| AC |
| OA |
| OB |
| AB |
| OB |
| OA |
| OC |
| AB |
| ||||
|
|
| 0×(-2)+3×1 | ||||
|
| ||
| 5 |
| OC |
| AB |
| ||
| 5 |
| ||
| 5 |