题目内容
若xn+…+ax3+bx2+cx+4n=(x+4)n(n∈N+,n≥3)且a:b=3:2,则n=______.
依题意,a=
4n-3,b=
4n-2,
∵a:b=3:2,
∴
=
=
=
,
解得n=20.
故答案为:20.
| C | 3n |
| C | 2n |
∵a:b=3:2,
∴
| ||
|
| ||
|
| n-2 |
| 12 |
| 3 |
| 2 |
解得n=20.
故答案为:20.
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