题目内容
13.已知曲线C的参数方程为$\left\{{\begin{array}{l}{x=1+3t}\\{y=a{t^2}+2}\end{array}}$(t为参数,a∈R),点M(4,3)在曲线C上,则a=( )| A. | -2 | B. | 0 | C. | 1 | D. | 2 |
分析 令$\left\{\begin{array}{l}{1+3t=4}\\{a{t}^{2}+2=3}\end{array}\right.$,解方程组即可.
解答 解:解方程组$\left\{\begin{array}{l}{1+3t=4}\\{a{t}^{2}+2=3}\end{array}\right.$得$\left\{\begin{array}{l}{a=1}\\{t=1}\end{array}\right.$,
故选C.
点评 本题考查了参数方程的意义,属于基础题.
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