题目内容
| lim |
| n→∞ |
| 2n2+1 |
| 1+3+5+…+(2n-1) |
由于分母是等差数列的和，可先利用等差数列的求和公式求和，故有
=
=
(2+
)=2
故答案为2．
| lim |
| n→∞ |
| 2n2+1 |
| 1+3+5+…+(2n-1) |
| lim |
| n→∞ |
| 2n2+1 |
| n2 |
| lim |
| n→∞ |
| 1 |
| n2 |
故答案为2．
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题目内容
| lim |
| n→∞ |
| 2n2+1 |
| 1+3+5+…+(2n-1) |
| lim |
| n→∞ |
| 2n2+1 |
| 1+3+5+…+(2n-1) |
| lim |
| n→∞ |
| 2n2+1 |
| n2 |
| lim |
| n→∞ |
| 1 |
| n2 |