题目内容
若sin(180°+α)+cos(90°+α)=-a,则cos(270°-α)+2sin(360°-α)的值是( )
分析:利用诱导公式可求得sinα=
,继而可求得cos(270°-α)+2sin(360°-α)的值.
| a |
| 2 |
解答:解:∵sin(180°+α)+cos(90°+α)=-sinα-sinα=-a,
∴sinα=
.
∴cos(270°-α)+2sin(360°-α)
=cos(180°+90°-α)+2sin(360°-α)
=-cos(90°-α)-2sinα
=-sinα-2sinα
=-3sinα=-3×
=-
a.
故选B.
∴sinα=
| a |
| 2 |
∴cos(270°-α)+2sin(360°-α)
=cos(180°+90°-α)+2sin(360°-α)
=-cos(90°-α)-2sinα
=-sinα-2sinα
=-3sinα=-3×
| a |
| 2 |
| 3 |
| 2 |
故选B.
点评:本题考查三角函数的诱导公式,求得sinα=
是关键,属于基础题.
| a |
| 2 |
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