题目内容
正三角形ABC边长为2,设
=2
,
=3
,则
·
=________.
![]()
-2
【解析】∵
=
+
=
+![]()
,
=
-
=![]()
-
,∴
·
=(
+![]()
)·(![]()
-
)=![]()
·
+![]()
·
-![]()
·
-
2=
×2×2×
+
×2×2×
+
×2×2×
-22=-2.
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题目内容
正三角形ABC边长为2,设
=2
,
=3
,则
·
=________.
![]()
-2
【解析】∵
=
+
=
+![]()
,
=
-
=![]()
-
,∴
·
=(
+![]()
)·(![]()
-
)=![]()
·
+![]()
·
-![]()
·
-
2=
×2×2×
+
×2×2×
+
×2×2×
-22=-2.