题目内容
计算(
)-
+log2
-(
-1)lg1+
lg4+lg5=______.
| 1 |
| 8 |
| 2 |
| 3 |
| 1 |
| 16 |
| 3 |
| 1 |
| 2 |
原式=2-3×(-
)+log22-4-(
-1)lg1+
lg22+lg5
=22+(-4)-(
-1)0+lg2+lg5
=-1+(lg2+lg5)
=-1+lg(2×5)=0.
故答案为:0.
| 2 |
| 3 |
| 3 |
| 1 |
| 2 |
=22+(-4)-(
| 3 |
=-1+(lg2+lg5)
=-1+lg(2×5)=0.
故答案为:0.
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