题目内容
| 2cos10°-sin20° |
| sin70° |
A.
| B.
| C.
| D.
|
原式=
=
=
=
.
故答案为C
| 2cos(30°-20°)-sin20° |
| sin70° |
=
| 2(cos30°•cos20°+sin30°•sin20°)-sin20° |
| sin70° |
=
| ||
| cos20° |
=
| 3 |
故答案为C
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