Question

已知lg(x-2)、lg|2y|、lg16x成等差数列,则点(x,y)的轨迹方程是__________________.

Answer 1

解析:由已知得2lg|2y|=lg(x-2)+lg16x,

变形为y²=4x(x-2)(y＞0,x＞2).

整理为4x²-8x-y²=0(x＞2,y＞0).

答案:4x²-8x-y²=0(x＞2,y＞0).