题目内容
数列{-2n2+29n+3}中最大项的值是( )A.107 B.108 C.108
D.109
解析:由于an=-2n2+29n+3=-2［n2-n+(
)2］+3+2×
=-2(n-
)2+3+
,
当n=7时,an最大且最大项为-2×(
)2+3+
=108.故选B.
答案:B
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题目内容
数列{-2n2+29n+3}中最大项的值是( )A.107 B.108 C.108 D.109
解析:由于an=-2n2+29n+3=-2［n2-n+()2］+3+2×
=-2(n-)2+3+,
当n=7时,an最大且最大项为-2×()2+3+=108.故选B.
答案:B