题目内容
已知cos(
-α)=
,则cos(
+α)-sin2(α-
)=
.
| π |
| 6 |
| ||
| 3 |
| 5π |
| 6 |
| π |
| 6 |
2-
| ||
| 3 |
2-
| ||
| 3 |
分析:根据诱导公式得出cos(
+α)=-cos(
-α),sin2(α-
)=1-cos2(
-α),然后将已知条件代入即可求出结果.
| 5π |
| 6 |
| π |
| 6 |
| π |
| 6 |
| π |
| 6 |
解答:解:cos(
+α)=cos[π-(
-α)]=-cos(
-α)=-
sin2(α-
)=sin2[-(
-α)]=1-cos2(
-α)=1-(-
)2=
∴cos(
+α)-sin2(α-
)
=-
-
=-
.
故答案为:-
| 5π |
| 6 |
| π |
| 6 |
| π |
| 6 |
| ||
| 3 |
sin2(α-
| π |
| 6 |
| π |
| 6 |
| π |
| 6 |
| ||
| 3 |
| 2 |
| 3 |
∴cos(
| 5π |
| 6 |
| π |
| 6 |
=-
| ||
| 3 |
| 2 |
| 3 |
=-
| ||
| 3 |
故答案为:-
| ||
| 3 |
点评:此题考查了诱导公式以及两角和与差公式,熟练掌握公式是解题的关键,属于中档题.
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