题目内容
若非零实数a、b、c满足5a=2b=
,则
+
的值等于( )
| 10c |
| c |
| a |
| c |
| b |
分析:由5a=2b=
,设5a=2b=
=m,由指数式和对数式的互化用对数形式表示a,b,c,由此能求出
+
的值.
| 10c |
| 10c |
| c |
| a |
| c |
| b |
解答:解:∵5a=2b=
,
∴设5a=2b=
=m,
a=log5m,b=log2m,c=2lgm,
∴
+
=
+
=2lgm(logm5+logm2)
=2lgm•logm10
=2.
故选B.
| 10c |
∴设5a=2b=
| 10c |
a=log5m,b=log2m,c=2lgm,
∴
| c |
| a |
| c |
| b |
| 2lgm |
| log5m |
| 2lgm |
| log2m |
=2lgm(logm5+logm2)
=2lgm•logm10
=2.
故选B.
点评:本题考查指数式和对数式的互化,解题时要认真审题,仔细解答.
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