题目内容
求
的值．
| lim |
| x→0 |
| ex-e-x-2x |
| x-sinnx |
应用罗比塔法则，
=
=0．(n≠1)
当n=1时，
=
=
=
=2
| lim |
| x→0 |
| ex-e-x-2x |
| x-sinnx |
| lim |
| x→0 |
| ex-e-x-2 |
| 1-ncosnx |
当n=1时，
| lim |
| x→0 |
| ex-e-x-2x |
| x-sinnx |
| lim |
| x→0 |
| ex-e-x-2 |
| 1-cosx |
| lim |
| x→0 |
| ex-e-x |
| sinx |
| lim |
| x→0 |
| ex-e-x |
| cosx |
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