ÌâÄ¿ÄÚÈÝ

ÏÂͼÊÇʵÑéÊÒÖÆÈ¡²¢¼ìÑéÒÒÏ©ÐÔÖʵÄ×°ÖÃͼ£¬IÊÔ¹Ü×°ÓÐäåË®£¬IIÊÔ¹Ü×°ÓÐËáÐÔ¸ßÃÌËá¼ØÈÜÒº¡£
£¨1£©Ð´³öÉú³ÉÏ©µÄ»¯Ñ§·½³Ìʽ____________________£»
£¨2£©Å¨ÁòËáµÄ×÷ÓÃÊÇ____________£»
£¨3£©IÊÔ¹ÜÖеÄÏÖÏóÓÐ____________£¬ ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________£»IIÊÔ¹ÜÖз¢ÉúµÄ·´Ó¦ÊôÓÚ
__________·´Ó¦£¨Ìî·´Ó¦ÀàÐÍ£©£»
£¨4£©ÊµÑéµÄ×îºó½×¶Î£¬·´Ó¦»ìºÏÎïµÄÒºÌå»á±äºÚÉ«£¬²¢ÓÐÆøÌåÔÓÖÊÉú³É£¬Òª³ýÈ¥ÕâЩÔÓÖÊ£¬Ó¦ÔÚÏ´ÆøÆ¿ÖÐ×°Èë_________ÈÜÒº£» ÈôÎÞ´Ë×°Öã¬IÊÔ¹ÜÖл¹¿ÉÄÜ·¢ÉúÁíÍâÒ»¸ö·´Ó¦£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________¡£
£¨5£©Ñé´¿ºó£¬ÔÚµ¼¹ÜÄ©¶ËµãȼÉú³ÉµÄÆøÌ壬Ëù¹Û²ìµ½µÄÏÖÏóÊÇ____________£¬ ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________________________¡£
£¨1£©
£¨2£©´ß»¯¼Á¡¢ÍÑË®¼Á
£¨3£©äåË®ÍÊÉ«£¬ÊԹܵײ¿ÓÐÉÙÁ¿ÓÍ×´Î£»Ñõ»¯
£¨4£©NaOH£»SO2+Br2+2H2O=SO42-+2Br-+4H+
£¨5£©»ðÑæÃ÷ÁÁ£¬²¢°éÓкÚÑÌ£»
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø