ÌâÄ¿ÄÚÈÝ
£¨16·Ö£©ÎªÁ˺ÏÀíÀûÓû¯Ñ§ÄÜ£¬È·±£°²È«Éú²ú£¬»¯¹¤Éè¼ÆÐèÒª³ä·Ö¿¼ÂÇ»¯Ñ§·´Ó¦µÄìʱ䣬²¢²ÉÈ¡ÏàÓ¦´ëÊ©¡£»¯Ñ§·´Ó¦µÄìʱäͨ³£ÓÃʵÑé½øÐвⶨ£¬Ò²¿É½øÐÐÀíÂÛÍÆËã¡£
¢ÅʵÑé²âµÃ£¬5g¼×´¼ÔÚÑõÆøÖгä·ÖȼÉÕÉú³É¶þÑõ»¯Ì¼ÆøÌåºÍҺ̬ˮʱÊͷųö113.5kJµÄÈÈÁ¿£¬ÊÔд³ö¼×´¼È¼ÉÕµÄÈÈ»¯Ñ§·½³Ìʽ£º____________________________________¡£
¢ÆÏÂͼÊÇij±Ê¼Ç±¾µçÄÔÓü״¼È¼ÁÏµç³ØµÄ½á¹¹Ê¾Òâͼ¡£![]()
·Åµçʱ¼×´¼Ó¦´Ó______´¦Í¨È루Ìî¡°a¡±»ò¡°b¡±£©£¬µç³ØÄÚ²¿H£«Ïò_____£¨Ìî¡°×ó¡±»ò¡°ÓÒ¡±£©Òƶ¯¡£Ð´³öµç³Ø¸º¼«µÄµç¼«·´Ó¦Ê½£º_______________________________¡£
¢ÇÓÉÆøÌ¬»ù̬Ô×ÓÐγÉ1mol»¯Ñ§¼üÊͷŵÄ×îµÍÄÜÁ¿½Ð¼üÄÜ¡£´Ó»¯Ñ§¼üµÄ½Ç¶È·ÖÎö£¬»¯Ñ§·´Ó¦µÄ¹ý³Ì¾ÍÊÇ·´Ó¦ÎïµÄ»¯Ñ§¼üµÄÆÆ»µºÍÉú³ÉÎïµÄ»¯Ñ§¼üµÄÐγɹý³Ì¡£ÔÚ»¯Ñ§·´Ó¦¹ý³ÌÖУ¬²ð¿ª»¯Ñ§¼üÐèÒªÏûºÄÄÜÁ¿£¬Ðγɻ¯Ñ§¼üÓÖ»áÊÍ·ÅÄÜÁ¿¡£
| »¯Ñ§¼ü | H£H | N£H | N¡ÔN |
| ¼üÄÜ/kJ¡¤mol£1 | 436 | a | 945 |
¢ÈÒÀ¾Ý¸Ç˹¶¨ÂÉ¿ÉÒÔ¶ÔijЩÄÑÒÔͨ¹ýʵÑéÖ±½Ó²â¶¨µÄ»¯Ñ§·´Ó¦µÄìÊ±ä½øÐÐÍÆËã¡£
ÒÑÖª£ºC(s£¬Ê¯Ä«)£«O2(g)£½CO2(g) ¡÷H1£½£393.5kJ¡¤mol£1
2H2(g)£«O2(g)£½2H2O(l) ¡÷H2£½£571.6kJ¡¤mol£1
2C2H2(g)£«5O2(g)£½4CO2(g)£«2H2O(l) ¡÷H3£½£2599kJ¡¤mol£1
¸ù¾Ý¸Ç˹¶¨ÂÉ£¬¼ÆËã2C(s£¬Ê¯Ä«)£«H2(g)£½C2H2(g)·´Ó¦µÄìʱä¡÷H£½________¡£
£¨1£©2CH3OH(l)+3O2(g)=2CO2(g)+2H2O(l) ¡÷H=£½£1452.8kJ¡¤mol-1
£¨2£©a ÓÒ CH3OH+H2O-6e-=CO2+6H+ £¨3£©391 £¨4£©¡÷H="+226.7" kJ¡¤mol-1
½âÎö