ÌâÄ¿ÄÚÈÝ
ÓÃ50mL 0.55mol/L NaOHÈÜÒººÍ50mL 0.25mol/L H2SO4ÈÜÒºÀ´×öÖкÍÈȲⶨµÄʵÑ飬²âµÃÈÜÒºÔÚ·´Ó¦Ç°ºóµÄζȱ仯Ϊt1¡æ¡«t2¡æ £¨t2>t1£©,»ìºÏºóÈÜÒºµÄ±ÈÈÈÈÝΪc = 4.18J£¯£¨g¡¤¡æ£©,ÈÜÒºµÄÃܶȶ¼½üËÆÎª1g/mL£¬ÖкÍÈÈ¡÷H=____________________(Ìî±í´ïʽ£¬²»Óû¯¼ò)
Èô½«H2SO4ÈÜÒº»»³ÉÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄCH3COOHÈÜÒº£¬²âµÃµÄ¡÷H______Ìî(¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°Ïàͬ¡±£©
Èô½«Ï¡ÁòËá»»³ÉŨÁòËáÀ´×ö¸ÃʵÑ飬²âµÃµÄ¡÷H___________£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°Ïàͬ¡±£©
Æ«´ó ƫС
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿