ÌâÄ¿ÄÚÈÝ
12£®ÔÚÈçͼËùʾµÄ×°ÖÃÖУ¬ÈôֱͨÁ÷µç5minʱ£¬Íµç¼«ÖÊÁ¿Ôö¼Ó2.16g£®ÊԻشðÏÂÁÐÎÊÌ⣮£¨1£©µçÔ´ÖÐXµç¼«ÎªÖ±Á÷µçÔ´µÄ¸º¼«£®
£¨2£©Ð´³öÒÔϵ缫·´Ó¦Ê½
¢ÙCÖеÄAgµç¼«Ag-e-¨TAg+£®
¢ÚBÖеÄÑô¼«4OH--4e-¨T2H2O+O2¡ü£®
£¨3£©BÖеç½âÒ»¶Îʱ¼äºó£¬ÈÜÒºµÄPHÈçºÎ±ä»¯±äС£¨Ì±ä´ó¡¢±äС»ò²»±ä£©£¬ÈôҪʹÈÜÒº»Ö¸´Ô×´£¬¿ÉÏòÈÜÒºÖмÓÈëÊÊÁ¿µÄCuO»òCuCO3£®
£¨4£©AÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ2Cl-+2H2O$\frac{\underline{\;ͨµç\;}}{\;}$Cl2¡ü+H2¡ü+2OH-£®
£¨5£©Èôµç½âÖеÄÖ±Á÷µçԴΪ¼×ÍéȼÁÏµç³Ø£¨KOHΪµç½âÖÊ£©£¬Ôòµç³ØµÄ¸º¼«·´Ó¦Ê½ÎªCH4-8e-+10OH-=CO32-+7H2O£®
£¨6£©Í¨µç5minʱ£¬BÖй²ÊÕ¼¯224mL£¨±ê×¼×´¿öÏ£©ÆøÌ壬ÈÜÒºÌå»ýΪ200mL£¬ÔòͨµçǰCuSO4ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.025mol/L£¨Éèµç½âǰºóÈÜÒºÌå»ýÎޱ仯£©£®
·ÖÎö £¨1£©ÓÉ͵缫µÄÖÊÁ¿Ôö¼Ó£¬ÔòCuµç¼«ÎªÒõ¼«£¬¿ÉÖªXΪµçÔ´µÄ¸º¼«£»
£¨2£©¢ÙCÖеÄAgµç¼«ÎªÑô¼«£¬Òø±¾Éí·Åµç£»
¢ÚBÖеÄÑô¼«ÉÏOH-·Åµç£»
£¨3£©BÖеç½âÁòËáÍÈÜÒºÉú³ÉÁòËᣬpH¼õС£»±¾×Å¡°³öÀ´Ê²Ã´£¬¼ÓÈëʲôÎïÖʵÄ×éºÏ¡±µÄÔÀíÀ´·ÖÎö¼ÓÈëµÄÎïÖÊ£»
£¨4£©AΪµç½âÂÈ»¯¼ØÈÜÒº£¬Éú³ÉÂÈÆø¡¢ÇâÆøºÍÇâÑõ»¯¼Ø£»
£¨5£©ÔÚ¼îÐÔ¼×ÍéȼÁÏµç³ØÖУ¬¸º¼«ÉÏÊǼ×Íé·ÅµçÉú³ÉCO32-£¬½áºÏ¼îÐÔ»·¾³À´·ÖÎöµç¼«·½³ÌʽµÄÊéд£»
£¨6£©¸ù¾Ýµç¼«·´Ó¦¼°µç×ÓÊØºãÀ´¼ÆË㣮
½â´ð ½â£º£¨1£©ÓÉ͵缫µÄÖÊÁ¿Ôö¼Ó£¬·¢ÉúAg++e-¨TAg£¬ÔòCuµç¼«ÎªÒõ¼«£¬AgΪÑô¼«£¬YΪÕý¼«£¬¿ÉÖªXΪµçÔ´µÄ¸º¼«£¬
¹Ê´ð°¸Îª£º¸º£»
£¨2£©¢ÙCÖеÄAgµç¼«ÎªÑô¼«£¬Òø±¾Éí·Åµç£¬¹Êµç¼«·´Ó¦Îª£ºAg-e-¨TAg+£¬
¹Ê´ð°¸Îª£ºAg-e-¨TAg+£»
¢ÚBÖеÄÑô¼«ÉÏOH-·Åµç£¬µç¼«·´Ó¦Îª£º4OH--4e-¨T2H2O+O2¡ü£¬
¹Ê´ð°¸Îª£º4OH--4e-¨T2H2O+O2¡ü£»
£¨3£©BÖеç½âÁòËáÍÈÜÒºÉú³ÉÁòËᣬÈÜÒºÖÐÇâÀë×ÓŨ¶ÈÔö´ó£¬pH¼õС£»B³ØÖÐÒõ¼«µÄµç¼«·´Ó¦Îª£ºCu2++2e-=Cu£¬Ñô¼«µç¼«·´Ó¦Îª£º4OH--4e-¨T2H2O+O2¡ü£¬¹Ê´ÓB³ØÖгöÀ´µÄÎïÖÊÓÐͺÍÑõÆø£¬¹ÊҪʹµç½âÒº¸´Ô£¬Ó¦¼ÓÈëCuO»òCuCO3£¬
¹Ê´ð°¸Îª£º±äС£»CuO»òCuCO3£»
£¨4£©AΪµç½âÂÈ»¯¼ØÈÜÒº£¬Éú³ÉÂÈÆø¡¢ÇâÆøºÍÇâÑõ»¯¼Ø£¬·½³ÌʽΪ2Cl-+2H2O$\frac{\underline{\;ͨµç\;}}{\;}$Cl2¡ü+H2¡ü+2OH-£¬
¹Ê´ð°¸Îª£º2Cl-+2H2O$\frac{\underline{\;ͨµç\;}}{\;}$Cl2¡ü+H2¡ü+2OH-£»
£¨5£©ÔÚ¼îÐÔ¼×ÍéȼÁÏµç³ØÖУ¬¸º¼«ÉÏÊǼ×Íé·ÅµçÉú³ÉCO32-£¬½áºÏ¼îÐÔ»·¾³¿ÉÖªµç¼«·½³ÌʽΪ£ºCH4-8e-+10OH-=CO32-+7H2O£¬
¹Ê´ð°¸Îª£ºCH4-8e-+10OH-=CO32-+7H2O£»
£¨6£©CÖÐÒõ¼«·´Ó¦ÎªAg++e-¨TAg£¬n£¨Ag£©=$\frac{2.16g}{108g/mol}$=0.02mol£¬Ôò×ªÒÆµÄµç×ÓΪ0.02mol£¬BÖÐÑô¼«·´Ó¦Îª4OH--4e-¨T2H2O+O2¡ü£¬Ôò×ªÒÆ0.02molµç×ÓÉú³ÉÑõÆøÎª0.005mol£¬ÆäÌå»ýΪ0.005mol¡Á22.4L/mol=0.112L=112mL£¬ÔòÔÚÒõ¼«Ò²Éú³É112mLÆøÌ壬ÓÉ2H++2e-¨TH2¡ü£¬ÔòÇâÆøµÄÎïÖʵÄÁ¿Îª0.005mol£¬¸Ã·´Ó¦×ªÒƵĵç×ÓΪ0.01mol£¬ÔòCu2++2e-¨TCuÖÐ×ªÒÆ0.01molµç×Ó£¬ËùÒÔCu2+µÄÎïÖʵÄÁ¿Îª0.005mol£¬Í¨µçǰc£¨CuSO4£©=$\frac{0.005mol}{0.2L}$=0.025 mol•L-1£»
¹Ê´ð°¸Îª£º0.025mol/L£®
µãÆÀ ±¾Ì⿼²éµç½âÔÀí£¬Ã÷È·Cuµç¼«µÄÖÊÁ¿Ôö¼ÓÊǽâ´ð±¾ÌâµÄÍ»ÆÆ¿Ú£¬²¢Ã÷È··¢ÉúµÄµç¼«·´Ó¦¼°µç×ÓÊØºã¼´¿É½â´ð£¬×¢Òâ¼ÆËãʱµç×ÓÊØºãµÄÓ¦Óã¬ÌâÄ¿ÄѶÈÖеȣ®
| A£® | Àë×Ó»¯ºÏÎïÖÐÒ»¶¨²»º¬·Ç¼«ÐÔ¹²¼Û¼ü | |
| B£® | Ô×Ó¾§ÌåµÄÈÛµãÒ»¶¨¸ßÓÚÆäËû¾§Ìå | |
| C£® | ½ðÊô¾§ÌåµÄ¶Ñ»ý·½Ê½µÄ¿Õ¼äÀûÓÃÂÊ×îµÍµÄÊÇPo | |
| D£® | ¹¹³É¾§ÌåµÄÁ£×ÓÒ»¶¨º¬Óл¯Ñ§¼ü |
£¨1£©µÚÒ»ÖÖ·½°¸£ºÇë´ÓͼÖÐÑ¡ÓÃÊʵ±µÄ×°Öã¬Éè¼ÆÒ»¸öʵÑ飬²â¶¨CaC2ÊÔÑùµÄ´¿¶È£®ËùѡװÖõÄÁ¬½Ó˳ÐòΪ£¨°´ÆøÁ÷·½Ïò£¬ÓýӿÚ×Öĸ±íʾ£©£ºfcdb£®ÈôʵÑéʱ³ÆÈ¡µÄÊÔÑùΪ m g£¬²úÉúµÄÒÒȲÔÚ±ê×¼×´¿öϵÄÌå»ýΪn mL£¬´ËÊÔÑùÖÐCaC2µÄÖÊÁ¿·ÖÊýΪ$\frac{64n}{22400m}$¡Á100%£®
£¨2£©µÚ¶þÖÖ·½°¸£º¸ù¾ÝÊÔÑùºÍË®ÔÚ×¶ÐÎÆ¿Öз´Ó¦Ç°ºóÖÊÁ¿µÄ±ä»¯£¬²â¶¨CaC2µÄÖÊÁ¿·ÖÊý£®ÏȳÆÈ¡ÊÔÑù6.80g¡¢×¶ÐÎÆ¿ºÍË®µÄÖÊÁ¿Îª188.00g£¬ÔÙ½«ÊÔÑù¼ÓÈë×¶ÐÎÆ¿ÖУ¬Óõç×ÓÌìÆ½³ÆÁ¿£¬ÊµÑé×°ÖÃÈçͼËùʾ£®·´Ó¦¹ý³ÌÖÐÿ¸ôÏàͬʱ¼ä²âµÃµÄÊý¾ÝÈç±í£º
| ×¶ÐÎÆ¿+Ë®+ÊÔÑù | |||||
| ¶ÁÊý´ÎÊý | µÚÒ»´Î | µÚ¶þ´Î | µÚÈý´Î | µÚËÄ´Î | µÚÎå´Î |
| ÖÊÁ¿/g | 192.80 | 192.30 | 192.10 | 192.00 | 192.00 |
¢ÚÓÐͬѧÈÏΪÓôË×°ÖòâµÃµÄÊý¾Ý±ÈÕæÊµÖµÐ¡£¬ÊÔ·ÖÎöÔÒò£ºË®ÕôÆøËæC2H2»Ó·¢£®
¢ÛÈçºÎÔÚÔÓÐ×°ÖÃÉϽøÐиĽø£¬Ê¹½á¹û¸ü¼Ó׼ȷ£®Çë¼òÒªÃèÊöÄãµÄ·½°¸£ºÔÚ×¶ÐÎÆ¿¿ÚÌí¼ÓÒ»¸ö´øÓÐÎÞË®ÂÈ»¯¸ÆµÄ¸ÉÔï¹ÜµÄµ¥¿×ÏðƤÈû£®
£¨3£©µÚÈýÖÖ·½°¸£º³ÆÈ¡6.80gÊÔÑù£¬ÓÃ200mL 1.85mol/LµÄÏ¡ÑÎËáÈܽ⣬½«ËùµÃµÄÈÜÒº×ªÒÆÖÁ500mLÈÝÁ¿Æ¿ÖУ¬¶¨ÈÝ£®È¡20mL¶¨ÈݺóµÄÈÜÒº£¬ÓÃ0.20mol/LµÄNaOHÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄNaOHÈÜÒº30.00mL£¬Ôò6.80gÊÔÑùÖÐCaC2µÄÖÊÁ¿Îª5.12g£®
| A£® | ±ù-»ìºÏÎï | B£® | ´¿¼î-ÑÎ | ||
| C£® | ³ÎÇåʯ»ÒË®-´¿¾»Îï | D£® | ½à¾»µÄ¿ÕÆø-´¿¾»Îï |
| A£® | 100mL | B£® | 200mL | C£® | 220mL | D£® | 240mL |
| A£® | CuSO4 | B£® | CO2 | C£® | HCl | D£® | CH3CH2OH |