ÌâÄ¿ÄÚÈÝ

ÒÑÖªÒ»¸ö̼ԭ×ÓÉÏÁ¬ÓÐÁ½¸öôÇ»ùʱ£¬Ò×·¢ÉúÏÂÁÐת»¯£º

¡£Çë¸ù¾ÝÏÂͼÍê³ÉÏÂÁÐÎÊÌ⣺

£¨1£©EÖк¬ÓеĹÙÄÜÍŵÄÃû³ÆÊÇ_____________£»¢ÛµÄ·´Ó¦ÀàÐÍÊÇ_____________£¬C¸úÐÂÖÆµÄÇâÑõ»¯Í­·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________________________________¡£

£¨2£©ÒÑÖªBµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª162£¬ÆäȼÉÕ²úÎïÖÐn(CO2)¡Ãn(H2O)=2¡Ã1¡£ÔòBµÄ·Ö×ÓʽΪ_______________£¬FµÄ·Ö×ÓʽΪ_______________¡£

£¨3£©ÔÚµçÄÔоƬÉú²úÁìÓò£¬¸ß·Ö×Ó¹â×è¼ÁÊǹâ¿ÌÊ´0.11 ¦ÌmÏß¿íоƬµÄ¹Ø¼ü¼¼Êõ¡£FÊÇÕâÖָ߷Ö×Ó¹â×è¼ÁÉú²úÖеÄÖ÷ÒªÔ­ÁÏ¡£F¾ßÓÐÈçÏÂÌØµã£º¢ÙÄܸúFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£»¢ÚÄÜ·¢Éú¼Ó¾Û·´Ó¦£»¢Û·¼»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ¡£FÔÚÒ»¶¨Ìõ¼þÏ·¢Éú¼Ó¾Û·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________________________________________________¡£

£¨4£©»¯ºÏÎïGÊÇFµÄͬ·ÖÒì¹¹Ì壬ËüÊôÓÚ·¼Ïã×廯ºÏÎÄÜ·¢ÉúÒø¾µ·´Ó¦¡£G¿ÉÄÜÓÐ____________Öֽṹ£¬Ð´³öÆäÖÐÈÎÒ»ÖÖͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ_________________________¡£

£¨1£©ôÈ»ù  Ñõ»¯·´Ó¦  CH3CHO+2Cu(OH)2CH3COOH+Cu2O¡ý+2H2O

£¨2£©C10H10O2  C8H8O

(4)4  »ò»ò¼äλ¡¢ÁÚλÈÎÒ»ÖÖ

½âÎö£º

£¨2£©ÒòΪBµÄȼÉÕ²úÎïÖÐn(CO2)¡Ãn(H2O)=2¡Ã1£¬¶øC¡¢HÔªËØÈ«²¿À´Ô´ÓÚB£¬ËùÒÔBµÄ·Ö×ÓʽCxHyO2ÖÐx=y£¬ÓÚÊÇÓÐ12x+1¡¤x+32=162£¬µÃx=10£¬¹ÊBµÄ·Ö×ÓʽΪC10H10O2¡£ÓÉBÓëÏ¡H2SO4¼ÓÈȵõ½E£¨CH3COOH£©ÓëF¿ÉÖªBΪõ¥£¬·¢ÉúµÄÊÇõ¥µÄË®½â£¬¼´Ò×ÖªFµÄ·Ö×ÓʽΪC8H8O¡£

£¨3£©FÄÜÓëFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦È·¶¨ÓзÓôÇ»ù¡£

FÄÜ·¢Éú¼Ó¾Û·´Ó¦È·¶¨´æÔÚ¡£

·¼»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖÈ·¶¨¡ªOHÓë³Ê¶Ôλ¡£

£¨4£©GÊôÓÚ·¼Ïã×廯ºÏÎ˵Ã÷ÆäÖꬱ½»·£»¿É·¢ÉúÒø¾µ·´Ó¦£¬ËµÃ÷º¬¡ªCHO¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø