ÌâÄ¿ÄÚÈÝ
£¨9·Ö£©¹¤ÒµÉÏ´Óº£Ë®ÖÐÌáÈ¡äåµÄ·½·¨ÈçÏ£º
¢Ù½«ÕôÁó£¨ÖƵˮ£©ºóŨËõµÄº£Ë®ÓÃÁòËá½øÐÐËữ£»
¢ÚÏòËữµÄº£Ë®ÖÐͨÈë×ãÁ¿ÂÈÆø£¬Ê¹äåÀë×Óת»¯Îªäåµ¥ÖÊ£»
¢ÛÏòÉÏÊöÈÜÒºÖÐͨÈë¿ÕÆøºÍË®ÕôÆø£¬½«äåµ¥ÖÊ´µÈëÊ¢ÓжþÑõ»¯ÁòË®ÈÜÒºµÄÎüÊÕËþÄÚת»¯³ÉÇâäåË᣻¢ÜÏòÎüÊÕËþÄÚͨÈëÊÊÁ¿µÄÂÈÆø£»
¢ÝÓÃËÄÂÈ»¯Ì¼ÝÍÈ¡ÎüÊÕËþÖеÄäåµ¥ÖÊ¡£
ÇëÍê³ÉÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚʵÑéÊÒÖÐÕôÁóº£Ë®ÖƵˮʱ£¬³£ÓõÄÒÇÆ÷³ýÁ˾ƾ«µÆ¡¢×¶ÐÎÆ¿¡¢Å£½Ç¹Ü¡¢ÀäÄý¹Ü¡¢Ê¯ÃÞÍø¼°±ØÒªµÄ¼Ð³ÖÒÇÆ÷£¬»¹ÐèÒªµÄ²£Á§ÒÇÆ÷ÓÐ £»ÕôÁóʱËé´ÉƬµÄ×÷ÓÃÊÇ____________________¡£
£¨2£©²½Öè¢ÚÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ
£¨3£©²½Öè¢ÛµÄÄ¿µÄÊÇʹäåµ¥Öʸ»¼¯£¬ÊÔд³öäåµ¥ÖÊÓë¶þÑõ»¯ÁòË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£·´Ó¦ÖÐ_________£¨Ð´»¯Ñ§Ê½£©ÊÇÑõ»¯¼Á¡£1molÑõ»¯¼ÁÔÚ·´Ó¦Öеõ½ molµç×Ó¡£
£¨4£©ÏÂÁÐÄÜ´úÌæËÄÂÈ»¯Ì¼À´ÝÍÈ¡äåµÄÊÔ¼ÁÊÇ £¨ÌîÐòºÅ£©
| A£®ÑÎËá | B£®¾Æ¾« | C£®ÒÒËá | D£®±½ |
£¨9·Ö£©£¨1£©ÕôÁóÉÕÆ¿£¨2·Ö£©£»·ÀÖ¹±©·Ð £¨2·Ö£©
£¨2£©C12+2Br££½ Br2+2C1£ £¨2·Ö£©
£¨3£©SO2 + Br2 + 2H2O £½ 2HBr + H2SO4 £¨2·Ö£©£» Br2£¨2·Ö£© 2 £¨2·Ö£©
£¨4£©D £¨2·Ö£©
½âÎö
| A¡¢º£Ë®ÖÐäåÔªËØÖ÷ÒªÒÔÐÎʽBr-´æÔÚ | B¡¢ÉÏÊö·´Ó¦ÊôÓÚÀë×Ó·´Ó¦ | C¡¢äåµ¥ÖʱÈÂȵ¥ÖÊ»îÆÃ | D¡¢ÉÏÊö·´Ó¦ÊôÓÚÑõ»¯»¹Ô·´Ó¦ |