ÌâÄ¿ÄÚÈÝ

¸ù¾ÝÒÔÏ¿òͼ¹ØÏµÌî¿Õ£¬ÒÑÖª·´Ó¦¢Ù¡¢¢ÛÊÇÎÒ¹ú»¯Ñ§¹¤ÒµÉú²úÖеÄÖØÒª·´Ó¦£¬D¡¢E³£ÎÂÏÂÎªÆøÌ壬X³£ÎÂÏÂΪÎÞÉ«ÎÞζ͸Ã÷ÒºÌ壬HÓëEÏà¶Ô·Ö×ÓÖÊÁ¿Ö®¼äµÄ¹ØÏµÎªMr(H)-Mr(E)=34£¬ÓÖÖªCµÄÑæÉ«·´Ó¦»ðÑæ³Ê»ÆÉ«£¬JΪºìºÖÉ«³Áµí¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)¹ÌÌåBµÄµç×ÓʽΪ____________£¬ÆäÖÐËù°üº¬µÄ»¯Ñ§¼üÓÐ____________¡£

(2)¹ÌÌåAµÄ»¯Ñ§Ê½Îª____________£¬ÆäÖзǽðÊôÔªËØµÄ»¯Ñ§¼ÛΪ____________¼Û¡£

(3)·´Ó¦¢ÜµÄÀë×Ó·½³ÌʽΪ________________¡£·´Ó¦¢ÝµÄ»¯Ñ§·½³ÌʽΪ_________________¡£

(4)ÓÃÍ­×÷µç¼«µç½âHÈÜÒº£¬Ñô¼«µÄµç¼«·´Ó¦Ê½Îª__________________________________¡£

(5)ÒÑ֪ÿÉú³É16 g E£¬·Å³ö106.625 kJÈÈÁ¿£¬Ôò·´Ó¦¢ÙµÄÈÈ»¯Ñ§·½³ÌʽΪ____________¡£

(1) Àë×Ó¼ü¡¢¹²¼Û¼ü(»ò·Ç¼«ÐÔ¼ü)

(2)FeS2  -1

(3)Fe2O3+6H+*2Fe3++3H2O

Fe2(SO4)3+6NaOH*2Fe(OH)3¡ý+3Na2SO4

(4)Cu-2e-*Cu2+

(5)FeS2(s)+11/4O2(g)1/2Fe2O3(s)+2SO2(g)£»¦¤H=-853 kJ/mol

½âÎö£ºX³£ÎÂÏÂΪÎÞÉ«ÎÞζ͸Ã÷ÒºÌ壬֤Ã÷XÊÇH2O£¬Ôòµ­»ÆÉ«¹ÌÌåBΪNa2O2£¬C¡¢D·Ö±ðΪNaOH¡¢O2£»¢Ù¢ÛÊÇ»¯Ñ§¹¤ÒµÉú²úÖеÄÖØÒª·´Ó¦£¬JΪºìºÖÉ«³ÁµíFe(OH)3£¬¿ÉÍÆÖªA¡¢E¡¢F·Ö±ðΪFeS2¡¢SO2¡¢Fe2O3£¬ÔòGΪSO3£¬HΪH2SO4£¬IΪFe2(SO4)3.

(4)ÓÃÍ­×÷µç¼«µç½âH2SO4ʱ£¬Ñô¼«ÉÏÍ­·Åµç¶øÖð½¥Èܽ⣬Cu-2e-*Cu2+.


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø