ÌâÄ¿ÄÚÈÝ
ijͿóʯÖ÷Òªº¬Cu2(OH)2CO3£¬»¹º¬ÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ´ËÍ¿óʯΪÔÁÏÖÆ±¸CuSO4¡¤5H2O¼°CaCO3£¬²¿·Ö²½ÖèÈçÏ£º
![]()
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÈÜÒºA³ýº¬ÓÐCu2+Í⣬»¹¿ÉÄܺ¬ÓеĽðÊôÀë×ÓÓÐ________(ÌîÀë×Ó·ûºÅ)£¬ÑéÖ¤Ëù
º¬Àë×ÓËùÓõÄÊÔ¼ÁÊÇ______________¡£
£¨2£©¿ÉÓÃÉú³ÉµÄCO2ÖÆÈ¡ÓÅÖÊ̼Ëá¸Æ¡£ÖƱ¸Ê±£¬ÏÈÏòÂÈ»¯¸ÆÈÜÒºÖÐͨÈë°±Æø£¬ÔÙͨÈë
CO2¡£
¢ÙʵÑéÊÒͨ³£²ÉÓüÓÈÈÂÈ»¯ï§ºÍÇâÑõ»¯¸Æ»ìºÏÎïµÄ·½·¨ÖÆÈ¡°±Æø¡£Ä³Ñ§Ï°Ð¡×éѡȡÏÂͼËù¸ø²¿·Ö×°ÖÃÖÆÈ¡²¢ÊÕ¼¯´¿¾»µÄ°±Æø¡£
![]()
![]()
![]()
![]()
Èç¹û°´ÆøÁ÷·½ÏòÁ¬½Ó¸÷ÒÇÆ÷½Ó¿Ú£¬ÄãÈÏΪÕýÈ·µÄ˳ÐòΪa¡ú______¡¢______¡ú______¡¢______¡ú i¡£ÆäÖÐÓëiÏàÁ¬Â©¶·µÄ×÷ÓÃÊÇ______________¡£
¢ÚʵÑéÊÒÖл¹¿ÉÓùÌÌåÇâÑõ»¯ÄƺÍŨ°±Ë®ÖÆÈ¡ÉÙÁ¿°±Æø£¬ÏÂÁÐ×îÊʺÏÍê³É¸ÃʵÑéµÄ¼òÒ××°ÖÃÊÇ_________(Ìî±àºÅ)
![]()
£¨3£©²â¶¨Í¿óʯÖÐCu2(OH)2CO3ÖÊÁ¿°Ù·Öº¬Á¿µÄ·½·¨ÊÇ£ºa£®½«1.25gÍ¿óÊ¯ÖÆÈ¡µÄCuSO4¡¤5H2OÓÚ×¶ÐÎÆ¿ÖУ¬¼ÓÈëÊÊÁ¿Ë®ÍêÈ«Èܽ⣻b£®ÏòÈÜÒºÖмÓÈë100mL0.25mol/LµÄÇâÑõ»¯ÄÆÈÜҺʹCu2+ÍêÈ«³Áµí£»c£®¹ýÂË£»d£®ÂËÒºÖеÄÇâÑõ»¯ÄÆÈÜÒºÓÃ0.5mol/LÑÎËáµÎ¶¨ÖÁÖյ㣬ºÄÓÃ10mLÑÎËá¡£
¡¡ÔòÍ¿óʯÖÐCu2(OH)2CO3ÖÊÁ¿·ÖÊýΪ_____________¡£
£¨1£©Fe2+¡¢Fe3+£»ËáÐÔ¸ßÃÌËá¼ØÈÜÒº¡¢KSCNÈÜÒº¡££¨4·Ö£¬¸÷1·Ö£¬ÆäËûºÏÀí´ð°¸Ò²µÃ·Ö£©
£¨2£©¢Ùa¡úg¡¢h¡úe¡¢d¡ú i £¨2·Ö£©£¬·ÀÖ¹µ¹Îü£¨1·Ö£©£»¢ÚA£¨2·Ö£©
£¨3£©88.8%£¨2·Ö£©