ÌâÄ¿ÄÚÈÝ
ÏÂÁйØÓÚÈÈ»¯Ñ§·´Ó¦µÄÃèÊöÖÐÕýÈ·µÄÊÇ
A£®ÒÑÖªH+(aq)+OH-(aq)=H2O(1)£»¦¤H=-57.3kJ¡¤mol-1£¬
ÔòH2SO4ºÍBa(OH)2·´Ó¦µÄ·´Ó¦ÈȦ¤H=2¡Á£¨-57.3£©kJ¡¤mol-1
B£®È¼ÁÏµç³ØÖн«¼×´¼ÕôÆø×ª»¯ÎªÇâÆøµÄÈÈ»¯Ñ§·½³ÌʽÊÇCH3OH(g)+1/2O2(g)=CO2(g)+ 2H2(g)£»¦¤H=-192.9 kJ¡¤mol-1£¬ÔòCH3OHµÄȼÉÕÈÈΪ192.9 kl¡¤mol-1
C£®H2(g)µÄȼÉÕÈÈÊÇ285.8 kJ¡¤mol -1£¬Ôò2H2O(g)=2H2(g)+O2(g); ¦¤H = +571.6 kJ¡¤mol -1
D£®ÆÏÌÑÌǵÄȼÉÕÈÈÊÇ2 800 kJ¡¤mol -1£¬Ôòl£¯2C6H12O6(s)+3O2(g)=3CO2(g)+3H2O(1)£»
¦¤H = -1 400 kJ¡¤mol-1
D
½âÎö:
±¾Ì⿼²éÈÈ»¯Ñ§·½³ÌʽµÄÓйØÖªÊ¶£¬¹Ø¼üÔÚÓÚÃ÷È·Óйط´Ó¦Èȵĸ÷ÖÖ¸ÅÄî¼°ÈÈ»¯Ñ§·½³ÌʽµÄÊéд·½·¨¼°ÕýÎóÅжϡ£H2SO4ºÍBa(OH)2·´Ó¦Ê±»¹Éú³ÉBaSO4³Áµí£¬¹Ê·´Ó¦ÈÈ»¹°üÀ¨BaSO4³ÁµíµÄÉú³ÉÈÈ£¬¹ÊA´í£»È¼ÉÕÈȵ͍ÒåÊÇ1 molÎïÖÊÍêȫȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯ÎïËù·Å³öµÄÈÈÁ¿ÊǸÃÎïÖʵÄȼÉÕÈÈ£¬¼×´¼µÄȼÉÕÈÈÊÇ1 mol CH3OH(l) ÍêȫȼÉÕÉú³ÉҺ̬ˮºÍ¶þÑõ»¯Ì¼Ëù·Å³öµÄÈÈÁ¿£¬B¡¢C´í£»ÆÏÌÑÌǵÄȼÉÕÈÈÊÇ2800 kJ¡¤mol -1£¬¹Êl£¯2C6H12O6(s)+3O2(g)=3CO2(g)+3H2O(1)£»¦¤H = -1 400 kJ¡¤mol-1£¬DÕýÈ·¡£