ÌâÄ¿ÄÚÈÝ

ÏÂÁÐÐðÊö´íÎóµÄÊÇ

¢ÙÈÈÎȶ¨ÐÔ£ºH2O£¾HF£¾H2S ¢ÚFeÊǸ±×åÔªËØ ¢ÛIIA×åÔªËØµÄÑôÀë×ÓÓëÉÏÖÜÆÚÏ¡ÓÐÆøÌåÔªËØµÄÔ­×Ó¾ßÓÐÏàͬµÄºËÍâµç×ÓÅŲ¼ ¢ÜÔªËØÖÜÆÚ±íÖдÓIIIBµ½IIB×å10¸ö×ÝÐеÄÔªËØ¶¼ÊǽðÊôÔªËØ ¢Ý¶àµç×ÓÔ­×ÓÖУ¬ÔÚÀëºË½Ï½üµÄÇøÓòÄÚÔ˶¯µÄµç×ÓÄÜÁ¿½Ï¸ß ¢ÞÒÑÖªH2SO4(aq)£«2NaOH(aq)£½2H2O(l)£«Na2SO4(aq)¡÷H£½¡ª114.6kJ/mol£¬ÔòÖкÍÈÈΪ-57.3kJ¡¤mol-1 ¢ßÁ½¸ö·Ç½ðÊôÔªËØÔ­×Ó¼äÖ»¿ÉÄÜÐγɹ²¼Û¼ü£¬¶øº¬½ðÊôÔªËØµÄ»¯ºÏÎïÖÐÒ»¶¨º¬½ðÊô¼ü

A¡¢¢Ú¢Ü¢Þ B¡¢¢Ù¢Ý¢Þ C¡¢¢Ú¢Û¢Ü D¡¢¢Ù¢Ú¢Ý¢ß

D

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£º¢Ù·Ç½ðÊôÐÔÊÇF£¾O£¾S£¬ÔòÈÈÎȶ¨ÐÔ£ºHF£¾H2O£¾H2S£¬´íÎ󣻢ÚFeÊǵڢø×åÔªËØ£¬´íÎ󣻢ÛIIA×åÔªËØµÄÑôÀë×ÓÓëÉÏÖÜÆÚÏ¡ÓÐÆøÌåÔªËØµÄÔ­×Ó¾ßÓÐÏàͬµÄºËÍâµç×ÓÅŲ¼£¬ÕýÈ·£»¢ÜÔªËØÖÜÆÚ±íÖдÓIIIBµ½IIB×å10¸ö×ÝÐеÄÔªËØ¶¼ÊǽðÊôÔªËØ£¬ÕýÈ·£»¢Ý¶àµç×ÓÔ­×ÓÖУ¬ÔÚÀëºË½Ï½üµÄÇøÓòÄÚÔ˶¯µÄµç×ÓÄÜÁ¿½ÏµÍ£¬´íÎ󣻢ÞÖкÍÈÈÊÇÔÚÒ»¶¨Ìõ¼þÏ£¬Ï¡ÈÜÒºÖУ¬Ç¿ËáºÍÇ¿¼î·´Ó¦Éú³É1molˮʱËù·Å³öµÄÈÈÁ¿£¬ÒÑÖªH2SO4(aq)£«2NaOH(aq)£½2H2O(l)£«Na2SO4(aq)¡÷H£½¡ª114.6kJ/mol£¬ÔòÖкÍÈÈΪ57.3kJ¡¤mol-1£¬ÕýÈ·£»¢ßÁ½¸ö·Ç½ðÊôÔªËØÔ­×Ó¼äÖ»¿ÉÄÜÐγɹ²¼Û¼ü£¬¶øº¬½ðÊôÔªËØµÄ»¯ºÏÎïÖв»Ò»¶¨º¬½ðÊô¼ü£¬ÀýÈçÂÈ»¯ÄÆÖк¬ÓÐÀë×Ó¼ü£¬´íÎ󣬴ð°¸Ñ¡D¡£

¿¼µã£º¿¼²éÔªËØÖÜÆÚÂÉ¡¢»¯Ñ§¼ü¡¢ÖкÍÈÈÒÔ¼°ÔªËØÖÜÆÚ±íµÄ½á¹¹

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø