ÌâÄ¿ÄÚÈÝ
20-¢ñ(6·Ö)¹ÌÁò¼ÁÊǰÑúȼÉÕʱÉú³ÉµÄ¶þÑõ»¯ÁòÒÔÑεÄÐÎʽ¹Ì¶¨ÔÚ¯ÔüÖеÄÎïÖÊ£¬¿É
¼õÉÙ¶þÑõ»¯Áò¶Ô´óÆøµÄÎÛȾ¡£ÏÂÁÐÎïÖÊÖпÉÓÃ×ö¹ÌÁò¼ÁµÄÓÐ
A£® CaO B£®Na2C03 C£®NH4N03 D. P205
20-¢ò(14·Ö)ÒÔ»ÆÌú¿óΪÔÁÏ£¬²ÉÓýӴ¥·¨Éú²úÁòËáµÄÁ÷³Ì¿É¼òʾÈçÏ£º
![]()
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÔÚÂ¯ÆøÖÆÔìÖУ¬Éú³ÉS02µÄ»¯Ñ§·½³ÌʽΪ______________________________£»
(2)Â¯Æø¾«ÖƵÄ×÷ÓÃÊǽ«º¬S02µÄÂ¯Æø_______________¡¢_______________¼°¸ÉÔÈç¹ûÂ¯Æø²»¾¹ý¾«ÖÆ£¬¶ÔS02´ß»¯Ñõ»¯µÄÓ°ÏìÊÇ____________________________________ £º
(3)¾«ÖÆÂ¯Æø(º¬SO2Ìå»ý·ÖÊýΪ7£¥¡¢O2Ϊll£¥¡¢N2Ϊ82£¥)ÖÐS02ƽºâת»¯ÂÊÓëζȼ°Ñ¹Ç¿¹ØÏµÈçÏÂͼËùʾ¡£ÔÚʵ¼ÊÉú²úÖУ¬S02´ß»¯Ñõ»¯·´Ó¦µÄÌõ¼þÑ¡Ôñ³£Ñ¹¡¢450¡æ£»×óÓÒ(¶ÔӦͼÖÐAµã)£¬¶øÃ»ÓÐÑ¡ÔñS02ת»¯Âʸü¸ßµÄB»òCµã¶ÔÓ¦µÄ·´Ó¦Ìõ¼þ£¬ÆäÔÒò·Ö±ðÊÇ______________________________¡¢______________________________£»
(4)ÔÚS02´ß»¯Ñõ»¯É豸ÖÐÉèÖÃÈȽ»»»Æ÷µÄÄ¿µÄÊÇ_______________¡¢_______________£¬´Ó¶ø³ä·ÖÀûÓÃÄÜÔ´¡£
I A¡¢B
II
(1)4FeS2+11O2
2Fe2O3 +8SO2
(2)³ý³¾¡¢Ë®Ï´£»¿ó³¾£¬Éé¡¢ÎøµÈ»¯ºÏÎïµ¼ÖÂÖж¾£¬Ë®ÕôÆø¶ÔÉ豸ºÍÉú²úÓв»Á¼Ó°Ïì
£¨3£©²»Ñ¡Bµã£¬ÒòΪѹǿԽ´ó¶ÔÉ豸µÄͶ×ÊÔ½´ó£¬ÏûºÄµÄÄÜÁ¿¶à£»SO2ÔÁϵÄת»¯ÂÊÔÚ1¸ö´óÆøÑ¹ÏµÄת»¯ÂÊÒѾÊÇ97%×óÓÒ¡£ÔÙÌá¸ßѹǿ£¬SO2µÄת»¯ÂÊÌá¸ßµÄÓàµØºÜС£¬ËùÒÔ²ÉÓÃÒ»¸ö±ê×¼´óÆøÑ¹¼´¿É¡£
²»Ñ¡ÔñCµã£¬ÒòΪζÈÔ½µÍ£¬SO2ת»¯ÂÊËäÈ»¸ü¸ß£¬µ«´ß»¯¼ÁµÄ´ß»¯×÷ÓÃÊܵ½Ó°Ï죬450¡æÊ±£¬´ß»¯¼ÁµÄ´ß»¯Ð§ÂÊ×î¸ß£¬¹ÊÑ¡ÔñAµã£¬²»Ñ¡Cµã
£¨4£©ÀûÓ÷´Ó¦·Å³öµÄÈÈÁ¿Ô¤ÈÈÔÁÏÆø£¬ÉÏ²ã·´Ó¦Æø¾¹ýÈȽ»»»Æ÷ζȽµµ½¡æ½øÈëϲãʹ·´Ó¦¸ü¼ÓÍêÈ«
(20·Ö)
20-¢ñ(6·Ö)¹ÌÁò¼ÁÊǰÑúȼÉÕʱÉú³ÉµÄ¶þÑõ»¯ÁòÒÔÑεÄÐÎʽ¹Ì¶¨ÔÚ¯ÔüÖеÄÎïÖÊ£¬¿É
¼õÉÙ¶þÑõ»¯Áò¶Ô´óÆøµÄÎÛȾ¡£ÏÂÁÐÎïÖÊÖпÉÓÃ×ö¹ÌÁò¼ÁµÄÓÐ
| A£®CaO | B£®Na2C03 | C£®NH4N03 | D£®P205 |
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÔÚÂ¯ÆøÖÆÔìÖУ¬Éú³ÉS02µÄ»¯Ñ§·½³ÌʽΪ______________________________£»
(2)Â¯Æø¾«ÖƵÄ×÷ÓÃÊǽ«º¬S02µÄÂ¯Æø_______________¡¢_______________¼°¸ÉÔÈç¹ûÂ¯Æø²»¾¹ý¾«ÖÆ£¬¶ÔS02´ß»¯Ñõ»¯µÄÓ°ÏìÊÇ _____________ _______________ £º
(3)¾«ÖÆÂ¯Æø(º¬SO2Ìå»ý·ÖÊýΪ7£¥¡¢O2Ϊll£¥¡¢N2Ϊ82£¥)ÖÐS02ƽºâת»¯ÂÊÓëζȼ°Ñ¹Ç¿¹ØÏµÈçÏÂͼËùʾ¡£ÔÚʵ¼ÊÉú²úÖУ¬S02´ß»¯Ñõ»¯·´Ó¦µÄÌõ¼þÑ¡Ôñ³£Ñ¹¡¢450¡æ£»×óÓÒ(¶ÔӦͼÖÐAµã)£¬¶øÃ»ÓÐÑ¡ÔñS02ת»¯Âʸü¸ßµÄB»òCµã¶ÔÓ¦µÄ·´Ó¦Ìõ¼þ£¬ÆäÔÒò·Ö±ðÊÇ______________________________¡¢______________________________£»
(4)ÔÚS02´ß»¯Ñõ»¯É豸ÖÐÉèÖÃÈȽ»»»Æ÷µÄÄ¿µÄÊÇ_______________¡¢_______________£¬´Ó¶ø³ä·ÖÀûÓÃÄÜÔ´¡£
20-¢ñ(6·Ö)¹ÌÁò¼ÁÊǰÑúȼÉÕʱÉú³ÉµÄ¶þÑõ»¯ÁòÒÔÑεÄÐÎʽ¹Ì¶¨ÔÚ¯ÔüÖеÄÎïÖÊ£¬¿É
¼õÉÙ¶þÑõ»¯Áò¶Ô´óÆøµÄÎÛȾ¡£ÏÂÁÐÎïÖÊÖпÉÓÃ×ö¹ÌÁò¼ÁµÄÓÐ
A£® CaO B£®Na2C03 C£®NH4N03 D. P205
20-¢ò(14·Ö)ÒÔ»ÆÌú¿óΪÔÁÏ£¬²ÉÓýӴ¥·¨Éú²úÁòËáµÄÁ÷³Ì¿É¼òʾÈçÏ£º
![]()
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÔÚÂ¯ÆøÖÆÔìÖУ¬Éú³ÉS02µÄ»¯Ñ§·½³ÌʽΪ______________________________£»
(2)Â¯Æø¾«ÖƵÄ×÷ÓÃÊǽ«º¬S02µÄÂ¯Æø_______________¡¢_______________¼°¸ÉÔÈç¹ûÂ¯Æø²»¾¹ý¾«ÖÆ£¬¶ÔS02´ß»¯Ñõ»¯µÄÓ°ÏìÊÇ____________________________________£º
(3)¾«ÖÆÂ¯Æø(º¬SO2Ìå»ý·ÖÊýΪ7£¥¡¢O2Ϊll£¥¡¢N2Ϊ82£¥)ÖÐS02ƽºâת»¯ÂÊÓëζȼ°Ñ¹Ç¿¹ØÏµÈçÏÂͼËùʾ¡£ÔÚʵ¼ÊÉú²úÖУ¬S02´ß»¯Ñõ»¯·´Ó¦µÄÌõ¼þÑ¡Ôñ³£Ñ¹¡¢450¡æ£»×óÓÒ(¶ÔӦͼÖÐAµã)£¬¶øÃ»ÓÐÑ¡ÔñS02ת»¯Âʸü¸ßµÄB»òCµã¶ÔÓ¦µÄ·´Ó¦Ìõ¼þ£¬ÆäÔÒò·Ö±ðÊÇ______________________________¡¢______________________________£»
(4)ÔÚS02´ß»¯Ñõ»¯É豸ÖÐÉèÖÃÈȽ»»»Æ÷µÄÄ¿µÄÊÇ_______________¡¢_______________£¬´Ó¶ø³ä·ÖÀûÓÃÄÜÔ´¡£