ÌâÄ¿ÄÚÈÝ
4£®Ò»¶¨Î¶ÈÏ£¬ÔÚ2LµÄÃܱÕÈÝÆ÷ÖУ¬X¡¢Y¡¢ZÈýÖÖÆøÌåµÄÁ¿ËæÊ±¼ä±ä»¯µÄÇúÏßÈçͼ1Ëùʾ£º£¨1£©´Ó·´Ó¦¿ªÊ¼µ½10s£¬ÓÃZ±íʾµÄ·´Ó¦ËÙÂÊΪ0.079mol/£¨L•s£©£®
£¨2£©YµÄת»¯ÂÊΪ79%£®
£¨3£©¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪX£¨g£©+Y£¨g£©?2Z£¨g£©£®
£¨4£©¸ÃζÈÏ ƽºâ³£ÊýKµÄ±í´ïʽΪ$\frac{{c}^{2}£¨Z£©}{c£¨X£©•c£¨Y£©}$
£¨5£©10sºóµÄijһʱ¿Ì£¨t1£©¸Ä±äÁËÍâ½çÌõ¼þ£¬ÆäËÙÂÊËæÊ±¼äµÄ±ä»¯Í¼ÏóÈçͼ2Ëùʾ£ºÔòÏÂÁÐ˵·¨·ûºÏ¸ÃͼÏóµÄÊÇC¡¢D£®
A£®t1ʱ¿Ì£¬Ôö´óÁËXµÄŨ¶È
B£®t1ʱ¿Ì£¬Éý¸ßÁËÌåϵζÈ
C£®t1ʱ¿Ì£¬ËõСÁËÈÝÆ÷Ìå»ý
D£®t1ʱ¿Ì£¬Ê¹ÓÃÁË´ß»¯¼Á£®
·ÖÎö £¨1£©¸ù¾Ýv=$\frac{¡÷c}{¡÷t}$¼ÆËã·´Ó¦ËÙÂÊ£»
£¨2£©YµÄת»¯ÂÊΪ$\frac{±ä»¯Á¿}{ÆðʼÁ¿}¡Á100%$£»
£¨3£©¸ù¾ÝÎïÖʵÄÁ¿µÄ±ä»¯Ó뻯ѧ¼ÆÁ¿Êý³ÊÕý±ÈÊéд»¯Ñ§·½³Ìʽ£»
£¨4£©Æ½ºâ³£ÊýKµÈÓÚÉú³ÉÎïŨ¶ÈÃÝÖ®»ý±ÈÉÏ·´Ó¦ÎïŨ¶ÈÃÝÖ®»ý£»
£¨5£©ÓÉͼÏó¿ÉÖªÕýÄæ·´Ó¦ËÙÂÊÔö´ó£¬Æ½ºâÃ»ÒÆ¶¯£®
½â´ð ½â£º£¨1£©¦Í£¨Z£©=$\frac{\frac{1.58mol}{2L}}{10s}$=0.079mol/£¨L•s£©£¬¹Ê´ð°¸Îª£º0.079mol/£¨L•s£©£»
£¨2£©YµÄת»¯ÂÊΪ$\frac{±ä»¯Á¿}{ÆðʼÁ¿}¡Á100%$=$\frac{1-0.21}{1}$¡Á100%=79%£¬¹Ê´ð°¸Îª£º79%£»
£¨3£©ÓÉͼÏó¿ÉÒÔ¿´³ö£¬·´Ó¦µ½10sʱ£¬XµÄÎïÖʵÄÁ¿¼õС£¬±ä»¯ÖµÎª1.20mol-0.41mol=0.79mol£¬
YµÄÎïÖʵÄÁ¿¼õС£¬±ä»¯ÖµÎª1.0mol-0.21mol=0.79mol£¬ÔòX¡¢YΪ·´Ó¦Î
ZµÄÎïÖʵÄÁ¿Ôö¶à£¬±ä»¯ÖµÎª1.58mol£¬ÎªÉú³ÉÎ
¸ù¾ÝÎïÖʵÄÁ¿µÄ±ä»¯Ó뻯ѧ¼ÆÁ¿Êý³ÊÕý±È£¬
ÔòÓÐn£¨X£©£ºn£¨Y£©£ºn£¨Z£©=0.79mol£º0.79mol£º1.58mol=1£º1£º2£¬
ËùÒÔ·´Ó¦µÄ·½³ÌʽΪX£¨g£©+Y£¨g£©?2Z£¨g£©£¬¹Ê´ð°¸Îª£ºX£¨g£©+Y£¨g£©?2Z£¨g£©£»
£¨4£©·´Ó¦µÄ·½³ÌʽΪX£¨g£©+Y£¨g£©?2Z£¨g£©£¬Æ½ºâ³£ÊýKµÈÓÚÉú³ÉÎïŨ¶ÈÃÝÖ®»ý±ÈÉÏ·´Ó¦ÎïŨ¶ÈÃÝÖ®»ý£¬ËùÒÔK=$\frac{{c}^{2}£¨Z£©}{c£¨X£©•c£¨Y£©}$£¬¹Ê´ð°¸Îª£º$\frac{{c}^{2}£¨Z£©}{c£¨X£©•c£¨Y£©}$£»
£¨5£©ÓÉͼÏó¿ÉÖªÕýÄæ·´Ó¦ËÙÂÊÔö´ó£¬Æ½ºâÃ»ÒÆ¶¯£»
A£®t1ʱ¿Ì£¬Ôö´óÁËXµÄŨ¶È£¬Æ½ºâÕýÒÆ£¬²»·ûºÏÌâÒ⣬¹ÊA´íÎó£»
B£®t1ʱ¿Ì£¬Éý¸ßÁËÌåϵζȣ¬Æ½ºâÒÆ¶¯£¬²»·ûºÏÌâÒ⣬¹ÊB´íÎó
C£®t1ʱ¿Ì£¬ËõСÁËÈÝÆ÷Ìå»ý£¬ËÙÂÊÔö´ó£¬ÓÉÓÚ·´Ó¦Ç°ºó¼ÆÁ¿ÊýÏàµÈ£¬Æ½ºâ²»Òƶ¯£¬·ûºÏÌâÒ⣬¹ÊCÕýÈ·£»
D£®t1ʱ¿Ì£¬Ê¹ÓÃÁË´ß»¯¼Á£¬ËÙÂÊÔö´ó£¬Æ½ºâ²»Òƶ¯£¬·ûºÏÌâÒ⣬¹ÊDÕýÈ·£»
¹Ê´ð°¸Îª£ºC¡¢D£®
µãÆÀ ±¾Ì⿼²é·´Ó¦ËÙÂʵļÆËãÆ½ºâͼÏóÎÊÌ⣬ÌâÄ¿ÄѶȲ»´ó£¬×¢Òâ°ÑÎÕÎïÖʵÄÁ¿µÄ±ä»¯Ó뻯ѧ¼ÆÁ¿Êý³ÊÕý±È£¬ÒÔ´ËÊéд»¯Ñ§·½³Ìʽ£®
| A£® | Fe2£¨SO4£©3Ò×ÈÜÓÚË®£¬¿ÉÓÃ×÷¾»Ë®¼Á | |
| B£® | Al2O3ÈÛµã¸ß£¬¿ÉÓÃ×÷Ä͸ßβÄÁÏ | |
| C£® | Ìú±ÈͽðÊôÐÔÇ¿£¬¿ÉÓÃFeCl3¸¯Ê´Cu¿ÌÖÆÓ¡Ë¢µç·°å | |
| D£® | NaHCO3ÈÜÓÚË®³Ê¼îÐÔ£¬¿É×÷¿¹ËáÒ©£¬·þÓÃʱºÈЩ´×ÄÜÌá¸ßҩЧ |
| A£® | v£¨A£©=0.4mol/£¨L•s£© | B£® | v£¨B£©=0.5mol/£¨L•s£© | C£® | v£¨C£©=0.6mol/£¨L•s£© | D£® | v£¨D£©=0.7mol/£¨L•s£© |
| A£® | ³£ÎÂÏ£¬Ïò´×ËáÈÜÒºÖмÓÈëÉÙÁ¿µÄË®£¬ÈÜÒºÖÐc£¨H+£©½«Ôö´ó | |
| B£® | ³£ÎÂÏ£¬2NO£¨g£©+2CO£¨g£©?N2£¨g£©+2CO2£¨g£©ÄÜ×Ô·¢½øÐУ¬Ôò¸Ã·´Ó¦µÄ¡÷H£¼0 | |
| C£® | ÁòËáͱ¥ºÍÈÜÒº½µµÍζÈʱÓо§ÌåÎö³ö£¬¿ÉÓÃìØÅоÝÀ´½âÊÍ | |
| D£® | ÓÃCH3COOHÈÜÒº×öµ¼µçʵÑ飬µÆÅݺܰµ£¬Ò»¶¨ÄÜÖ¤Ã÷CH3COOHÊÇÈõµç½âÖÊ |
| A£® | µÈŨ¶ÈNaHSO4ºÍBa£¨OH£©2Á½ÈÜÒºµÈÌå»ý»ìºÏH++SO42-+Ba2++OH-¨TBaSO4¡ý+H2O | |
| B£® | ÔÚº¬ÓÐMn2+µÄÈÜÒºÖмÓÈëÏ¡ÏõËáËữ£¬ÔÙ¼ÓÈëPbO2·´Ó¦ÌåϵÏÔ×ϺìÉ«5PbO2+2Mn2++4H+¨T5Pb2++2MnO4-+2H2O | |
| C£® | ÁòËáÑÇÌúÈÜÒºÖмÓÈë¹ýÑõ»¯ÇâÈÜÒº£º2Fe2++H2O2+2H+¨T2Fe3++2H2O | |
| D£® | Na2O2ͶÈëH218OÖУº2H218O+2Na2O2¨T4Na++4OH-+18O2¡ü |
| A£® | ÈôX¡¢YÔ×ÓÐòÊýÏà²îl£¬YΪIIA×壬ÔòXÒ»¶¨ÊÇIIIA×å | |
| B£® | ÈôY£¨OH£©mÒ×ÈÜÓÚË®£¬ÔòX£¨OH£©nÒ»¶¨²»ÈÜÓÚË® | |
| C£® | ÈôHnXOmΪǿËᣬÔòXµÄÇ⻯ÎïÈÜÒºÓÚˮһ¶¨ÏÔËáÐÔ | |
| D£® | ÈôYÔªËØÐγɵĵ¥ÖÊÊÇÆøÌ壬ÔòXÔªËØÐγɵĵ¥ÖÊÒ»¶¨Ò²ÊÇÆøÌå |
| A£® | 14 gÒÒÏ©ºÍ±ûÏ©»ìºÏÆøÌåÖеÄÇâÔ×ÓÊýΪ2NA | |
| B£® | 1 molN2Óë4 mol H2·´Ó¦Éú³ÉµÄNH3·Ö×ÓÊýΪ2NA | |
| C£® | 1 molFeÈÜÓÚ¹ýÁ¿ÏõËᣬµç×Ó×ªÒÆÊýΪ2NA | |
| D£® | ±ê×¼×´¿öÏ£¬2.24 LCCl4º¬ÓеĹ²¼Û¼üÊýΪ0.4NA |