ÌâÄ¿ÄÚÈÝ
ÖÐÑëµçÊǪ́´Ó2001Äê6ÔÂ5ÈÕÆðÿÌì¶¼Òª±¨µÀ47¸öÖØµã³ÇÊÐµÄ¿ÕÆøÖÊÁ¿Ô¤±¨¡£°üÀ¨SO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿¡£Ä¿Ç°²â¶¨¿ÕÆøÖÐSO2º¬Á¿Ö÷ÒªÓÃÑõ»¯»¹Ô·´Ó¦·¨¡£¼ÙÈç¸øÄãÆøÌåÁ÷Ëٹܣ¨µ¥Î»Ê±¼äÄÚͨ¹ýÆøÌåµÄÌå»ýºã¶¨µ«ÎÞ³ý³¾ºÍÎüÊÕÆøÌåµÄ×÷Óã©¡°¡è¡±¡¢ÃܱÕÈÝÆ÷¡°¡õ¡±¡¢³¨¿ÚÒÇÆ÷¡°¡È¡±¡¢µ¼¹Ü¡°-»ò
¡¢0.0001mol?L-1µÄËáÐÔ¸ßÃÌËá¼ØÈÜÒº¡¢¿ÅÁ£Îü¸½¼Á¡¢Æ·ºìÊÔÒº¡¢pHÊÔÖ½µÈÒÇÆ÷ºÍÒ©Æ·£¬ÇëÉè¼ÆÒ»¸öʵÑé×°Ö㬲ⶨÄãËùÔÚµØÇø¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿¡£ÒÑÖª5SO2+2H2O+2MnO4-£¨×ÏÉ«£©=5SO42-+2Mn2+£¨ÎÞÉ«£©+4H+¡£»·¾³¿ÕÆøÖÊÁ¿±ê×¼ÈçÏ£º![]()
£¨1£©»³ö²â¶¨¿ÕÆøÖÐSO2ºÍ¿ÉÎüÈë¿ÅÁ£µÄº¬Á¿µÄʵÑé×°ÖÃͼ£¨²¢Ö¸³öÒÇÆ÷ÖеÄÒ©Æ·£©¡£
£¨2£©ÈôÆøÌåÁ÷ËÙ¹ÜÖÐÆøÌåÁ÷ËÙΪ5000cm3?min-1£¬µ±140minʱ20mL0.0001mol?L-1µÄËáÐÔ¸ßÃÌËá¼ØÈÜҺǡºÃÍËÉ«£¬Ôò¸ù¾ÝÎÒ¹ú¿ÕÆøÖÊÁ¿±ê×¼ºÍ²â¶¨½á¹ûÅжÏËù²â¶¨µØµãµÄ¿ÕÆøÖÐSO2µÄº¬Á¿ÊôÓÚ_________£¨ÌîÊý×Ö£©¼¶±ê×¼£¨»·¾³£©¡£
£¨3£©ÈôÒª²â¶¨¿ÕÆøÖпÉÎüÈë¿ÅÁ£µÄº¬Á¿£¬ÐèÒª²â³öµÄÊý¾ÝÓÐ__________________________________¡£
(1) ![]()
£¨2£©¶þ
£¨3£©ÎüÊÕǰºó¿ÅÁ£Îü¸½¼Á£¨º¬ÈÝÆ÷£©µÄÖÊÁ¿