ÌâÄ¿ÄÚÈÝ

¶ÁÏÂÁжíÂÞ˹Óë°Ä´óÀûÑÇ×ÔÈ»µØÀí·Ö²¼¼òͼ£¬»Ø´ðÏà¹ØÎÊÌ⣺£¨20·Ö£©

£¨1£©¶íÂÞ˹×ÔÈ»µØÀí·Ö²¼Í¼ÖУ¬Í¼ÀýABCËù±íʾµÄ×ÔÈ»»·¾³ÒªËØÊÇ           £¬ÆäÖÐͼÀýB·Ö²¼ÇøÓòµÄÃû³ÆÊÇ                          ¡£
£¨2£©°Ä´óÀûÑÇ×ÔÈ»µØÀí·Ö²¼Í¼Ëù±íʾµÄ×ÔÈ»»·¾³ÒªËØÊÇ              £¬ÆäÖÐE±íʾ             £¬F±íʾ                                ¡£
£¨3£©°Ä´óÀûÑÇ×ÔÈ»µØÀí·Ö²¼Í¼ÖÐD±íʾµÄµØÀíÊÂÎï·Ö²¼¹ã·º£¬Ô­ÒòÊÇ            
                            £»Ôì³ÉÄϻعéÏ߸½½ü¶«Î÷Á½°¶×ÔÈ»»·¾³²îÒìµÄÔ­Òò·Ö±ðÊÇ£º
¶«°¶                                                                     £»
Î÷°¶                                                                     ¡£
£¨4£©¶íÂÞ˹×ÔÈ»µØÀí·Ö²¼Í¼ÖÐËùʾµÄɽÂöÊÇÖØÒªµÄµØÀí·Ö½çÏߣ¬¾ÙÀý˵³ö¾ßÌåÄÚÈÝ£º
                                                                                                                                                                                
£¨5£©ËäÈ»¶íÂÞ˹ºÍ°Ä´óÀûÑǾ³ÄÚµØÊÆÆ½»ºµÄµØÇøÃæ»ý¹ã´ó£¬µ«Á½¹úµÄ¿ÑÖ³Ö¸Êý¶¼²»ÊǺܸߣ¬ÊÔ·ÖÎöÖ÷ÒªµÄ×ÔȻԭÒò¡£
¶íÂÞ˹£º                                                                                                                                                                       
°Ä´óÀûÑÇ£º                                                                                                                                                                  
£¨6£©¶íÂÞ˹Óë°Ä´óÀûÑǶ¼ÊÇÊÀ½ç¿óÒµ´ó¹ú£¬ÏÂÁи÷×é¿ó²úÖоùΪÁ½¹ú¸»ÓеÄÊÇ£¨   £©

A£®Ê¯ÓͺÍÌìÈ»ÆøB£®Ê¯ÓͺÍÌú¿óC£®ÃººÍÌìÈ»ÆøD£®ÃººÍÌú¿ó

£¨1£©µØÐΠ  ÖÐÎ÷²®ÀûÑǸßÔ­£¨2·Ö£©
£¨2£©Æøºò   µØÖк£Æøºò   Î´øº£ÑóÐÔÆøºò£¨3·Ö£©
£¨3£©³£ÄêÊܸ±ÈÈ´ø¸ßÆøÑ¹´ø¿ØÖÆ£¬Ê¢ÐÐϳÁÆøÁ÷£¨2·Ö£©
¶«°¶£ºÎ»ÓÚɽµØÓ­·çÆÂ£¬¶àµØÐÎÓ꣨1·Ö£©£»ÇÒÊÜÑØ°¶Å¯Á÷ÔöÎÂÔöʪ×÷Óã¨1·Ö£©¡£Î÷°¶£ºÎ»ÓÚ±³·çº£°¶£¨1·Ö£©£¬ÇÒÊÜÑØ°¶º®Á÷½µÎ¼õʪ×÷Óã¨1·Ö£©¡£
£¨4£©ÑÇÖÞÓëÅ·Ö޵ķֽçÏߣ» ¶«Å·Æ½Ô­ÓëÎ÷Î÷²®ÀûÑÇÆ½Ô­·Ö½çÏߣ¨2·Ö£©
£¨5£©¶íÂÞ˹£ºÎ³¶È¸ß£¬ÈÈÁ¿²»×㣬¶³ÍÁ·Ö²¼¹ã¡£°Ä´óÀûÑÇ£ºÆøºò¸Éºµ£¬É³Ä®Ãæ»ý¹ã¡££¨5·Ö£©
£¨6£©D£¨2·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¶ÁÏÂÁжíÂÞ˹Óë°Ä´óÀûÑÇ×ÔÈ»µØÀí·Ö²¼¼òͼ£¬»Ø´ðÏà¹ØÎÊÌ⣺

£¨1£©¶íÂÞ˹×ÔÈ»µØÀí·Ö²¼Í¼ÖУ¬Í¼ÀýABCËù±íʾµÄ×ÔÈ»»·¾³ÒªËØÊÇ            £¬ÆäÖÐͼÀýB·Ö²¼ÇøÓòµÄÃû³ÆÊÇ                           ¡£

£¨2£©°Ä´óÀûÑÇ×ÔÈ»µØÀí·Ö²¼Í¼Ëù±íʾµÄ×ÔÈ»»·¾³ÒªËØÊÇ               £¬ÆäÖÐE±íʾ              £¬F±íʾ                                 ¡£

£¨3£©°Ä´óÀûÑÇ×ÔÈ»µØÀí·Ö²¼Í¼ÖÐD±íʾµÄµØÀíÊÂÎï·Ö²¼¹ã·º£¬Ô­ÒòÊÇ            

                             £»Ôì³ÉÄϻعéÏ߸½½ü¶«Î÷Á½°¶×ÔÈ»»·¾³²îÒìµÄÔ­Òò·Ö±ðÊÇ£º

         ¶«°¶                                                                      £»

Î÷°¶                                                                      ¡£

£¨4£©¶íÂÞ˹×ÔÈ»µØÀí·Ö²¼Í¼ÖÐËùʾµÄɽÂöÊÇÖØÒªµÄµØÀí·Ö½çÏߣ¬¾ÙÀý˵³ö¾ßÌåÄÚÈÝ£º

                                                       

£¨5£©ËäÈ»¶íÂÞ˹ºÍ°Ä´óÀûÑǾ³ÄÚµØÊÆÆ½»ºµÄµØÇøÃæ»ý¹ã´ó£¬µ«Á½¹úµÄ¿ÑÖ³Ö¸Êý¶¼²»ÊǺܸߣ¬ÊÔ·ÖÎöÖ÷ÒªµÄ×ÔȻԭÒò¡£

¶íÂÞ˹£º                                                       

°Ä´óÀûÑÇ£º                                                  

£¨6£©¶íÂÞ˹Óë°Ä´óÀûÑǶ¼ÊÇÊÀ½ç¿óÒµ´ó¹ú£¬ÏÂÁи÷×é¿ó²úÖоùΪÁ½¹ú¸»ÓеÄÊÇ£¨    £©

A£®Ê¯ÓͺÍÌìÈ»Æø   B£®Ê¯ÓͺÍÌú¿ó  C£®ÃººÍÌìÈ»Æø      D£®ÃººÍÌú¿ó

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø