ÌâÄ¿ÄÚÈÝ

14£®Ì«ÑôÄÜÈÈË®Æ÷ÊǰÑÌ«ÑôÄÜת»¯ÎªÄÚÄܵÄÉè±¸Ö®Ò»Ä³Æ·ÅÆÌ«ÑôÄÜÈÈË®Æ÷ÿСʱƽ¾ù½ÓÊÕ4.2¡Á106 JµÄÌ«ÑôÄÜ£¬ÔÚijһÌìÓÐ10СʱµÄÓÐЧÕÕÉäʱ¼äÄÚ£¬½«ÈÈË®Æ÷ÖÐÖÊÁ¿Îª100kg¡¢³õÎÂΪ20¡æµÄˮζÈÉý¸ßµ½60¡æ£®Çó£º
£¨1£©ÈÈË®Æ÷ÖеÄË®ÎüÊÕµÄÈÈÁ¿Q£»[Ë®µÄ±ÈÈÈÈÝC=4.2¡Á103 J/£¨kg•¡æ£©]
£¨2£©ÈÈË®Æ÷µÄЧÂʦǣ»
£¨3£©Èô¸ÄÓÃÃºÆøÀ´¼ÓÈÈÕâЩˮ£¬ÐèÒªÍêȫȼÉÕ¶àÉÙǧ¿ËÃºÆø£¿£¨ÃºÆøµÄÈÈÖµq=4.2¡Á107J/kg£¬¼ÙÉèÃºÆøÈ¼ÉշųöµÄÈÈÁ¿È«²¿±»Ë®ÎüÊÕ£©

·ÖÎö £¨1£©ÖªµÀË®µÄÖÊÁ¿ºÍ³õΡ¢Ä©ÎÂÒÔ¼°±ÈÈÈÈÝ£¬¸ù¾ÝQ=cm£¨t-t0£©Çó³öË®ÎüÊÕµÄÈÈÁ¿£»
£¨2£©¸ù¾ÝÌâÒâÇó³öÈÈË®Æ÷½ÓÊÕµ½µÄÌ«ÑôÄÜ£¬¸ù¾Ý¦Ç=$\frac{Q}{E}$¡Á100%Çó³öÈÈË®Æ÷µÄЧÂÊ£»
£¨3£©ÃºÆøÈ¼ÉշųöµÄÈÈÁ¿È«²¿±»Ë®ÎüÊÕ£¬¸ù¾ÝQ·Å=Q=mqÇó³öËùÐèÃºÆøµÄÖÊÁ¿£®

½â´ð ½â£º£¨1£©ÈÈË®Æ÷ÖеÄË®ÎüÊÕµÄÈÈÁ¿£º
Q=cm£¨t-t0£©=4.2¡Á103J/£¨kg•¡æ£©¡Á100kg¡Á£¨60¡æ-20¡æ£©=1.68¡Á107J£»
£¨2£©ÈÈË®Æ÷10СʱÄÚ½ÓÊÕµ½µÄÌ«ÑôÄÜ£º
E=4.2¡Á106J/h¡Á10h=4.2¡Á107J£¬
ÈÈË®Æ÷µÄЧÂÊ£º
¦Ç=$\frac{Q}{E}$¡Á100%=$\frac{1.68¡Á1{0}^{7}J}{4.2¡Á1{0}^{7}J}$¡Á100%=40%£»
£¨3£©ÃºÆøÈ¼ÉշųöµÄÈÈÁ¿È«²¿±»Ë®ÎüÊÕ£¬¼´Q·Å=Q=1.68¡Á107J£¬
ÓÉQ·Å=mqµÃÐèҪȼÉÕÃºÆøµÄÖÊÁ¿£º
m¡ä=$\frac{{Q}_{·Å}}{q}$=$\frac{1.68¡Á1{0}^{7}J}{4.2¡Á1{0}^{7}J/kg}$=0.4kg£®
´ð£º£¨1£©ÈÈË®Æ÷ÖеÄË®ÎüÊÕµÄÈÈÁ¿Îª1.68¡Á107J£»
£¨2£©ÈÈË®Æ÷µÄЧÂÊΪ40%£»
£¨3£©Èô¸ÄÓÃÃºÆøÀ´¼ÓÈÈÕâЩˮ£¬ÐèÒªÍêȫȼÉÕ0.4kgµÄÃºÆø£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éµÄÊÇѧÉú¶ÔÈÈÁ¿¼ÆË㹫ʽ¡¢ÈÈÖµ¼ÆË㹫ʽ¡¢Ð§ÂʼÆË㹫ʽµÄÀí½âºÍÕÆÎÕ£¬ÊÇÒ»µÀ½ÏΪ¼òµ¥µÄÓ¦ÓÃÌ⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø