ÌâÄ¿ÄÚÈÝ

12£®Ò»´ÎÕÅÏÈÉúÍâ³ö°ìÊ£¬Ëû³Ë×øµÄ³ö×â³µÔÚÆ½Ö±¹«Â·ÉÏÔÈËÙÐÐÊ»£¬Èç±íΪËû³Ë³µµ½´ïÄ¿µÄµØÊ±³µÉϵçÄÔ×Ô¶¯¼Æ·ÑÆ÷´òÓ¡³öµÄ³µ·Ñ·¢Æ±£®
³µ    ºÅ£ºÉîB-T8888
³Ë³µÈÕÆÚ£º2004-04-18
ÉϳµÊ±¼ä£º10£º00
ϳµÊ±¼ä£º10£º05
µ¥    ¼Û£º2.00Ôª/km
Àï    ³Ì£º6.0km
½ð    ¶î£º16.00Ôª
Ç󣺣¨1£©Çó ³ö×â³µÐÐÊ»µÄʱ¼ä£®
£¨2£©Çó³ö×â³µÐÐÊ»µÄËٶȵÈÓÚ¶àÉÙkm/h£¿
£¨3£©Èô¸Ã³ö×â³µµÄÆð²½¼ÛΪ10Ôª£¬µ¥¼Û°´³¬¹ýÆð²½¼ÛÄÚ·³Ìºó¿ªÊ¼¼ÆË㣬ÔòÔÚÆð²½¼ÛÄÚ×î¶àÄܳ˶àÉÙ km£¿

·ÖÎö £¨1£©ÓɳµÆ±¿ÉµÃÉϳµÊ±¼äºÍϳµÊ±¼ä£¬Á½ÕߵIJî¾ÍÊÇÐÐʻʱ¼ä£»
£¨2£©Óɳµ·Ñ·¢Æ±¿ÉÖª£¬³ö×â³µÐÐÊ»µÄ·³ÌºÍËùÓõÄʱ¼ä£¬ÀûÓÃËٶȹ«Ê½v=$\frac{s}{t}$Çó³ö×â³µµÄËÙ¶È£»
£¨2£©ÖªµÀ¸Ã³ö×â³µµÄÆð²½¼ÛºÍËù½»³µ·Ñ£¬¿ÉÇ󳬹ýÆð²½¼ÛµÄÇ®Êý£¬¿ÉÇóÔÚÆð²½¼ÛÍâÐÐÊ»µÄ·³Ì

½â´ð ½â£º
£¨1£©Óɳµ·Ñ·¢Æ±¿ÉÖª£¬
t=10£º05-10£º00=5min£»
£¨2£©ÒÑÖªÐÐÊ»µÄ·³Ì£¬s=6km£¬
³ö×â³µµÄËÙ¶È£º
v=$\frac{s}{t}$=$\frac{6km}{5¡Á\frac{1}{60}h}$=72km/h
£¨2£©Èô¸Ã³ö×â³µµÄÆð²½¼ÛΪ10Ôª£¬½»·Ñ16Ôª£¬³¬¹ýÆð²½¼ÛµÄΪ6Ôª£¬ÔòÔÚÆð²½¼ÛÍâÐÐÊ»µÄ·³Ì£º
s¡ä=$\frac{6Ôª}{2.00km/Ôª}$=3km£®
´ð£º£¨1£©Çó ³ö×â³µÐÐÊ»µÄʱ¼äΪ5min£»
£¨2£©Çó³ö×â³µÐÐÊ»µÄËٶȵÈÓÚ72km/h£»
£¨3£©ÔÚÆð²½¼ÛÄÚ×î¶àÄܳË3 km£®

µãÆÀ ±¾Ì⿼²éÁËËٶȹ«Ê½µÄÓ¦Óã¬ÄÜ´Ó³ö×â³µÉϵóöÏà¹ØÐÅÏ¢Êǹؼü£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø