ÌâÄ¿ÄÚÈÝ
18£®£¨1£©Ä¾¿éϱíÃæÊܵ½Ë®µÄѹǿ£®
£¨2£©Ä¾¿éÔÚË®ÖÐÊܵ½µÄ¸¡Á¦£®
£¨3£©Ä¾¿éµ×ÃæµÄÃæ»ý£®
ÇëÄã°ïСÕŰÑËüÃÇÇó³öÀ´£®£¨g=9.8Å£/ǧ¿Ë£©
·ÖÎö £¨1£©¸ù¾Ýp=¦ÑghÇó³öľ¿éϱíÃæËùÊÜË®µÄѹǿ£»
£¨2£©¸ù¾ÝƯ¸¡Ìõ¼þ¸¡Á¦µÈÓÚÖØÁ¦Çó³öľ¿éËùÊÜË®µÄ¸¡Á¦£»
£¨3£©ÀûÓÃѹǿ¹«Ê½p=$\frac{F}{S}$Çó³öϵ×ÃæµÄÃæ»ý£®
½â´ð ½â£º£¨1£©Ä¾¿éϱíÃæÊܵ½Ë®µÄѹǿΪ£º
p=¦Ñgh
=1000kg/m3¡Á9.8N/kg¡Á0.06m
=588Pa£»
£¨2£©ÒòΪľ¿éƯ¸¡£¬ÆäËùÊܸ¡Á¦µÈÓÚÆäÖØÁ¦£¬
¹ÊËùÊܸ¡Á¦Îª£º
F¸¡=G=mg
=0.3kg¡Á9.8N/kg=2.94N£»
£¨3£©ÓÉp=$\frac{F}{S}$µÃ£º
ϱíÃæµÄÃæ»ýΪ£º
S=$\frac{{F}_{¸¡}}{p}$=$\frac{2.94N}{588Pa}$=5¡Á10-3m2£®
´ð£º£¨1£©Ä¾¿éϱíÃæÊܵ½Ë®µÄѹǿ588Pa£®
£¨2£©Ä¾¿éÔÚË®ÖÐÊܵ½µÄ¸¡Á¦2.94N£®
£¨3£©Ä¾¿éµ×ÃæµÄÃæ»ý5¡Á10-3m2£®
µãÆÀ ´ËÌâÖ÷Òª¿¼²éѧÉú¶ÔÓÚÒºÌåѹǿ¡¢¸¡Á¦µÄÀí½âºÍÕÆÎÕ£¬ÊÇÖп¼±Ø¿¼ÄÚÈÝ£¬ÊôÓÚÖØµã£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
13£®Ò»¸Ë¿Ì¶È׼ȷµÄ¸Ë³Ó£¬ÈôÆä³ÓíÈÉÏÕ³ÉÏÒ»¿éÖØÎÄÇôÓÃËü³Æ¶«Î÷ʱ£¬Æä¶ÁÊý£¨¡¡¡¡£©
| A£® | ±Èʵ¼ÊÖÊÁ¿´ó | B£® | ±Èʵ¼ÊÖÊÁ¿Ð¡ | ||
| C£® | Óëʵ¼ÊÖÊÁ¿Ïàͬ | D£® | Óëʵ¼ÊÖÊÁ¿µÄ¹ØÏµÄÑÒÔÈ·¶¨ |
3£®Óû²â¶¨Ò»Ìõµç×èË¿µÄµç×èÖµ£®Á¬½ÓÁËÈçͼ¼×ËùʾµÄµç·£®

£¨1£©±ÕºÏ¿ª¹Øºó£¬µçѹ±íʾÊý½Ó½ü6·ü£¬µçÁ÷±íʾÊý½Ó½üÁ㣬·ÖÎö¹ÊÕÏÔÒò¿ÉÄÜÊÇRx¶Ï·£®
£¨2£©Åųý¹ÊÕϺ󣬲â³ö3×éÊý¾Ý£¬µÚ1¡¢2´ÎʵÑéÊý¾Ý¼û±í£¬µÚ3×éÊý¾Ý¼û¡¢Í¼ÒÒ£¬ÆäÖеçÁ÷±íµÄʾÊýÊÇ0.46 °²£®ÊµÑé²âµÃ±»²âµç×èË¿µÄ×èÖµÊÇ3.7 Å·£®
| µçѹ/V | µçÁ÷/A | |
| 1 | 2.4 | 0.68 |
| 2 | 2.0 | 0.58 |
| 3 |
£¨2£©Åųý¹ÊÕϺ󣬲â³ö3×éÊý¾Ý£¬µÚ1¡¢2´ÎʵÑéÊý¾Ý¼û±í£¬µÚ3×éÊý¾Ý¼û¡¢Í¼ÒÒ£¬ÆäÖеçÁ÷±íµÄʾÊýÊÇ0.46 °²£®ÊµÑé²âµÃ±»²âµç×èË¿µÄ×èÖµÊÇ3.7 Å·£®