ÌâÄ¿ÄÚÈÝ
¾ê¾êÏëÓòâÃܶȵķ½·¨À´²âÁ¿Ëý¼ÒÉ«ÀÓ͵ÄÃܶȣ¬ÓÚÊÇËý½øÐÐÁËÒÔÏÂʵÑ飺

(1)½«ÌìÆ½·ÅÔÚ_______×ÀÃæÉÏ£¬°ÑÓÎÂëÒÆÖÁ³ÆÁ¿±ê³ßµÄ¡°0¡±¿Ì¶ÈÏßÉÏ£¬µ÷½Ú___________ʹÌìÆ½Æ½ºâ£»
(2)ÍùÉÕ±Öе¹ÈëÊÊÁ¿É«ÀÓÍ£¬ÓÃÌìÆ½²â³öÉÕ±ºÍÉ«ÀÓ͵Ä×ÜÖÊÁ¿M(Èçͼ¼×Ëùʾ)£¬ÔÙ½«ÉÕ±ÖеIJ¿·ÖÉ«ÀÓ͵¹ÈëÁ¿Í²ÖУ¬²â³öÉÕ±ºÍÊ£ÓàÉ«ÀÓ͵Ä×ÜÖÊÁ¿Îª23.8g£¬ÔòÁ¿Í²ÄÚÉ«ÀÓ͵ÄÖÊÁ¿m=_________g£»
(3)ͼÒÒÏÔʾµÄÊÇÁ¿Í²ÄÚÉ«ÀÓ͵ÄÌå»ýV£¬ÔòV=________cm3£»
(4)É«ÀÓ͵ÄÃܶÈ=__________g/cm3¡£
(1)½«ÌìÆ½·ÅÔÚ_______×ÀÃæÉÏ£¬°ÑÓÎÂëÒÆÖÁ³ÆÁ¿±ê³ßµÄ¡°0¡±¿Ì¶ÈÏßÉÏ£¬µ÷½Ú___________ʹÌìÆ½Æ½ºâ£»
(2)ÍùÉÕ±Öе¹ÈëÊÊÁ¿É«ÀÓÍ£¬ÓÃÌìÆ½²â³öÉÕ±ºÍÉ«ÀÓ͵Ä×ÜÖÊÁ¿M(Èçͼ¼×Ëùʾ)£¬ÔÙ½«ÉÕ±ÖеIJ¿·ÖÉ«ÀÓ͵¹ÈëÁ¿Í²ÖУ¬²â³öÉÕ±ºÍÊ£ÓàÉ«ÀÓ͵Ä×ÜÖÊÁ¿Îª23.8g£¬ÔòÁ¿Í²ÄÚÉ«ÀÓ͵ÄÖÊÁ¿m=_________g£»
(3)ͼÒÒÏÔʾµÄÊÇÁ¿Í²ÄÚÉ«ÀÓ͵ÄÌå»ýV£¬ÔòV=________cm3£»
(4)É«ÀÓ͵ÄÃܶÈ=__________g/cm3¡£
(1)ˮƽ£»Æ½ºâÂÝĸ£»(2)28.2£»(3)30£»(4)0.94¡£
£¨1£©ÌìÆ½Ê×ÏÈ·ÅÖÃÔÚˮƽ×ÀÃæÉÏ£¬µ÷½ÚƽºâÂÝĸʹÌìÆ½Æ½ºâ£»£¨2£©ÓÉÓÚM=52g£¬¹ÊÁ¿Í²ÄÚÉ«ÀÓ͵ÄÖÊÁ¿Îªm=52g£23.8g=28.2g£»£¨3£©¶ÁÈ¡Á¿Í²µÄʾÊýµÃ£¬ÆäÌå»ýV=30ml=30cm3£»£¨4£©É«ÀÓ͵ÄÃܶÈ=
=0.94g/cm3¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿