ÌâÄ¿ÄÚÈÝ

13£®ÈËÀàÕý»ý¼«¿ª·¢ºÍÀûÓÃÌ«ÑôÄÜ£¬ÈçÌ«ÑôÄÜÈÈË®Æ÷¡¢Ì«ÑôÄÜµç³ØµÈ£¬½­ÌÎÏëÖªµÀ¼ÒÖÐÌ«ÑôÄÜÈÈË®Æ÷ÎüÊÕÌ«ÑôÄܵı¾Á죬×öÁËÈçÏÂ̽¾¿£ºÌìÆøÇçÀÊʱ£¬½­ÌβâµÃÌ«ÑôÄÜÈÈË®Æ÷1hÄÚʹÖÊÁ¿Îª50kgµÄË®´Ó20¡æÉý¸ßµ½30¡æ£¬ÎÊ£º
£¨1£©1hÄÚË®ÎüÊÕÁ˶àÉÙÈÈÁ¿£¿[cË®=4.2¡Á103J/£¨kg•¡æ£©]
£¨2£©ÈôÓüÓÈȵķ½Ê½Ê¹Í¬ÖÊÁ¿µÄË®Éý¸ßÏàͬµÄζȣ¬ÔòÖÁÉÙÐèҪȼÉÕ¶àÉÙm3µÄÒº»¯Æø£¿£¨¼ÙÉèÒº»¯ÆøÈ¼ÉշųöµÄÈÈÁ¿µÄ70%±»Ë®ÎüÊÕ£¬Òº»¯ÆøµÄÈÈÖµÊÇ5.0¡Á107J/m3£©
£¨3£©ÇëÄã·Ö±ð˵˵ʹÓÃÌ«ÑôÄܵÄÒ»¸öÓŵãºÍÒ»¸ö²»×ãÖ®´¦£®

·ÖÎö £¨1£©ÒÑ֪ˮµÄ±ÈÈÈÈÝ¡¢ÖÊÁ¿¡¢³õκÍĩΣ¬ÀûÓÃÎüÈȹ«Ê½QÎü=cm£¨t-t0£©¼ÆËãË®ÎüÊÕµÄÈÈÁ¿£»
£¨2£©ÒÑÖªÈÈЧÂʺÍË®ÎüÊÕµÄÈÈÁ¿£¬¸ù¾ÝÈÈЧÂʹ«Ê½¦Ç=$\frac{{Q}_{Îü}}{{Q}_{·Å}}$Çó³öÒº»¯ÆøÈ¼ÉշųöµÄÈÈÁ¿£»ÀûÓÃÈÈÖµ¹«Ê½Q·Å=qV¿ÉÒÔÇó³öÐèÒªÒº»¯ÆøµÄÌå»ý£»
£¨3£©´Ó»·±£¡¢ÄÜÁ¿À´Ô´¡¢ÖÆ×÷³É±¾¡¢Ð§Âʵȷ½Ãæ·ÖÎöÌ«ÑôÄܵÄÓÅȱµã£®

½â´ð ½â£º
£¨1£©ÓÉÌâÖª£¬Ì«ÑôÄÜÈÈË®Æ÷1hÄÚʹÖÊÁ¿Îª50kgµÄË®´Ó20¡æÉý¸ßµ½30¡æ£¬
Ôò1hÄÚË®ÎüÊÕµÄÈÈÁ¿£º
QÎü=cm£¨t-t0£©=4.2¡Á103 J/£¨kg•¡æ£©¡Á50kg¡Á£¨30¡æ-20¡æ£©=2.1¡Á106J£»
£¨2£©¸ù¾ÝÈÈЧÂʹ«Ê½¦Ç=$\frac{{Q}_{Îü}}{{Q}_{·Å}}$¿ÉµÃ£¬Òº»¯ÆøÈ¼ÉշųöµÄÈÈÁ¿£º
Q·Å=$\frac{{Q}_{Îü}}{¦Ç}$=$\frac{2.1¡Á1{0}^{6}J}{70%}$=3¡Á106 J£»
ÓÉQ·Å=qV¿ÉµÃ£¬ÐèҪȼÉÕÒº»¯ÆøµÄÌå»ý£º
V=$\frac{{Q}_{·Å}}{q}$=$\frac{3¡Á1{0}^{6}J}{5.0¡Á1{0}^{7}J/{m}^{3}}$=0.06m3£»
£¨3£©Ì«ÑôÄܵÄÓŵ㣺Çå½àÎÞÎÛȾ£¬Ì«ÑôÄÜȡ֮²»¾¡£¬ÓÃÖ®²»½ß£»È±µã£º»ñÈ¡ÄÜÁ¿ÊÜËᄀ¢ÖçÒ¹¡¢ÒõÇçÌõ¼þµÄÏÞÖÆµÈ£®
´ð£º£¨1£©1hÄÚË®ÎüÊÕÁË2.1¡Á106JµÄÈÈÁ¿£»
£¨2£©ÈôÓüÓÈȵķ½Ê½Ê¹Í¬ÖÊÁ¿µÄË®Éý¸ßÏàͬµÄζȣ¬ÔòÖÁÉÙÐèҪȼÉÕ0.06m3µÄÒº»¯Æø£»
£¨3£©Ê¹ÓÃÌ«ÑôÄܵÄÓŵãÊÇÇå½àÎÞÎÛȾ£¬²»×ãÖ®´¦ÊÇ»ñȡ̫ÑôÄÜÊÜËᄀ¢ÖçÒ¹¡¢ÒõÇçÌõ¼þµÄÏÞÖÆ£®

µãÆÀ ±¾Ì⿼²éÁËÎüÈȹ«Ê½¡¢ÈÈЧÂʹ«Ê½ºÍÈÈÖµ¹«Ê½µÄÓ¦Óã¬ÒÔ¼°¶ÔÌ«ÑôÄÜÓÅȱµãµÄÈÏʶ£¬ÄѶÈÊÊÖУ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø