题目内容
若2x-3=1,y2-y=2,则3y2+2x2y-9y-(2y-x)的值为
8
8
.分析:先求得x,再把x=2代入3y2+2x2y-9y-(2y-x),将y2-y=2整体代入即可.
解答:解:∵2x-3=1,
∴x=2,
∵3y2+2x2y-9y-(2y-x)=3y2+8y-9y-(2y-2)
=3y2+8y-9y-2y+2
=3y2-3y+2
=3(y2-y)+2
=3×2+2
=8.
故答案为8.
∴x=2,
∵3y2+2x2y-9y-(2y-x)=3y2+8y-9y-(2y-2)
=3y2+8y-9y-2y+2
=3y2-3y+2
=3(y2-y)+2
=3×2+2
=8.
故答案为8.
点评:本题考查了整式的加减以及化简求值,是基础知识要熟练掌握.
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