题目内容
计算:(1)0-
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 2 |
(2)(-3
| 2 |
| 3 |
| 1 |
| 3 |
| 2 |
| 5 |
| 2 |
| 5 |
(3)|-7
| 3 |
| 8 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
分析:(1)(2)把小数化为分数,简化符号,再结合同分母的数计算;
(3)先计算绝对值里的,再简化符号,通分计算.
(3)先计算绝对值里的,再简化符号,通分计算.
解答:解:(1)0-
-(-3.25)+2
-7
=-
-7
+3
+2
=-8+6=-2
(2)(-3
)+(-2.4)-(-
)-(-4
)-(-4
)=-3
+2=-1
(3)|-7
+4
|+(-18
)+|-6-
|=-2
-18
+6
=-14
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
(2)(-3
| 2 |
| 3 |
| 1 |
| 3 |
| 2 |
| 5 |
| 2 |
| 5 |
| 1 |
| 3 |
| 1 |
| 3 |
(3)|-7
| 3 |
| 8 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 7 |
| 8 |
| 1 |
| 4 |
| 1 |
| 2 |
| 5 |
| 8 |
点评:本题主要考查有理数的异分母分数加减混合运算,通分是解题的关键.
练习册系列答案
相关题目