题目内容
当a,b分别取下列值时,求代数式a2-2ab-2b2的值:
(1)a=3,b=-1;
(2)a=-1
,b=-
.
(1)a=3,b=-1;
(2)a=-1
| 1 |
| 2 |
| 1 |
| 2 |
分析:分别把a、b的值代入进行计算即可得解.
解答:解:(1)a2-2ab-2b2
=32-2×3×(-1)-2×(-1)2
=9+6-2
=13;
(2)a2-2ab-2b2
=(-
)2-2×(-
)×(-
)-2×(-
)2
=
-
-
=
.
=32-2×3×(-1)-2×(-1)2
=9+6-2
=13;
(2)a2-2ab-2b2
=(-
| 3 |
| 2 |
| 3 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
=
| 9 |
| 4 |
| 3 |
| 2 |
| 1 |
| 2 |
=
| 1 |
| 4 |
点评:本题考查了代数式求值,比较简单,准确计算是解题的关键,计算时要注意运算符号的处理.
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