题目内容
先化简后求值(x-| x |
| x-1 |
| 1 |
| x2-1 |
| 1 | ||
|
分析:将每一个括号部分先通分,除法转化为乘法,约分,再将x的值化简,代值计算.
解答:解:(x-
)÷(1+
)
=
÷
=
•
=
,
当x=
=
+1时,
原式=
=2-
.
| x |
| x-1 |
| 1 |
| x2-1 |
=
| x(x-1)-x |
| x-1 |
| x2-1+1 |
| x2-1 |
=
| x2-2x |
| x-1 |
| (x+1)(x-1) |
| x2 |
=
| (x-2)(x+1) |
| x |
当x=
| 1 | ||
|
| 2 |
原式=
(
| ||||
|
| 2 |
点评:本题考查了二次根式的化简求值,解题时要遵循先化简后代入求值的原则.
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