题目内容
先化简,再求值:| x |
| x+2 |
| x2-x |
| x2+4x+4 |
| x |
| x-1 |
| 3 |
分析:这道求代数式值的题目,不应考虑把x的值直接代入,通常做法是先把除法转换为乘法化简,然后再代入求值.
解答:解:
÷
-
=
•
-
=
-
=
.
将x=1+
代入,
=
=
.
| x |
| x+2 |
| x2-x |
| x2+4x+4 |
| x |
| x-1 |
=
| x |
| x+2 |
| (x+2)2 |
| x(x-1) |
| x |
| x-1 |
=
| x+2 |
| x-1 |
| x |
| x-1 |
=
| 2 |
| x-1 |
将x=1+
| 3 |
| 2 |
| x-1 |
| 2 | ||
1+
|
| 2 |
| 3 |
| 3 |
点评:分式混合运算要注意先去括号;分子、分母能因式分解的先因式分解;除法要统一为乘法运算.
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