题目内容
计算或化简
(1)计算
-
;
(2)先化简:(
-a+1)÷
,再从1,-1,2中选一个你认为合适的数作为a的值代入求值.
(1)计算
| a+1 |
| a-1 |
| a2+a |
| a2-1 |
(2)先化简:(
| a2 |
| a+1 |
| a |
| a2-1 |
考点:分式的化简求值,分式的加减法
专题:
分析:(1)通分后相减,然后约分即可;
(2)先将括号内的部分通分,再将除法转化为乘法,因式分解后约分即可.
(2)先将括号内的部分通分,再将除法转化为乘法,因式分解后约分即可.
解答:解:(1)原式=
-
=
=
=
;
(2)(
-a+1)÷
=(
-
)•
=
•
=
,
当a=2时,原式=
=
.
| a2+2a+1 |
| (a-1)(a+1) |
| a2+a |
| (a-1)(a+1) |
=
| a2+2a+1-a2-a |
| (a-1)(a+1) |
=
| a+1 |
| (a-1)(a+1) |
=
| 1 |
| a-1 |
(2)(
| a2 |
| a+1 |
| a |
| a2-1 |
=(
| a2 |
| a+1 |
| a2-1 |
| a+1 |
| (a+1)(a-1) |
| a |
=
| 1 |
| a+1 |
| (a+1)(a-1) |
| a |
=
| a-1 |
| a |
当a=2时,原式=
| 2-1 |
| 2 |
| 1 |
| 2 |
点评:本题考查了分式的加减和分式的化简求值,熟悉因式分解是解题的关键.
练习册系列答案
相关题目