题目内容
11.下列各组数中,是二元一次方程5x-y=2的一个解的是( )| A. | $\left\{\begin{array}{l}{x=3}\\{y=1}\end{array}\right.$ | B. | $\left\{\begin{array}{l}{x=2}\\{y=0}\end{array}\right.$ | C. | $\left\{\begin{array}{l}{x=0}\\{y=2}\end{array}\right.$ | D. | $\left\{\begin{array}{l}{x=1}\\{y=3}\end{array}\right.$ |
分析 将x、y的值分别代入,能使方程左右两边相等即可.
解答 解:A、当$\left\{\begin{array}{l}{x=3}\\{y=1}\end{array}\right.$时,5x-y=14≠2,此选项错误;
B、当$\left\{\begin{array}{l}{x=2}\\{y=0}\end{array}\right.$时,5x-y=10≠2,此选项错误;
C、当$\left\{\begin{array}{l}{x=0}\\{y=2}\end{array}\right.$时,5x-y=-2≠2,此选项错误;
D、当$\left\{\begin{array}{l}{x=1}\\{y=3}\end{array}\right.$时,5x-y=2,此选项正确;
故选:D.
点评 本题主要考查二元一次方程的解得定义,掌握使二元一次方程两边的值相等的两个未知数的值,叫做二元一次方程的解是关键.
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