题目内容
19.若 $\left\{\begin{array}{l}x=2\\ y=1\end{array}\right.$是方程组$\left\{\begin{array}{l}ax-3y=1\\ x+by=5\end{array}\right.$的解,则a、b值为( )| A. | $\left\{\begin{array}{l}a=2\\ b=3.\end{array}\right.$ | B. | $\left\{\begin{array}{l}a=-2\\ b=3.\end{array}\right.$ | C. | $\left\{\begin{array}{l}a=2\\ b=-3.\end{array}\right.$ | D. | $\left\{\begin{array}{l}a=-2\\ b=-3.\end{array}\right.$ |
分析 把x与y的值代入方程组求出a与b的值即可.
解答 解:把$\left\{\begin{array}{l}{x=2}\\{y=1}\end{array}\right.$代入方程组得:$\left\{\begin{array}{l}{2a-3=1}\\{2+b=5}\end{array}\right.$,
解得:$\left\{\begin{array}{l}{a=2}\\{b=3}\end{array}\right.$,
故选A
点评 此题考查了二元一次方程组的解,方程组的解即为能使方程组中两方程都成立的未知数的值.
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