题目内容
若
=
=
=k,则k的值为( )
| 2b+2c |
| a |
| 2a+2c |
| b |
| 2a+2b |
| c |
| A、4 | B、0 |
| C、-2或0 | D、4或-2 |
分析:先将
=
=
=k变形为若
=
=
=
k,再根据等比性质计算,注意条件的限制.
| 2b+2c |
| a |
| 2a+2c |
| b |
| 2a+2b |
| c |
| a+b |
| c |
| b+c |
| a |
| c+a |
| b |
| 1 |
| 2 |
解答:解:∵
=
=
=k,
∴
=
=
=
k,
分情况进行:当a+b+c≠0时,根据等比性质,得
k=
=2,则k=4;
当a+b+c=0时,则a+b=-c,
k=-1,则k=-2.
故选D.
| 2b+2c |
| a |
| 2a+2c |
| b |
| 2a+2b |
| c |
∴
| b+c |
| a |
| a+c |
| b |
| a+b |
| c |
| 1 |
| 2 |
分情况进行:当a+b+c≠0时,根据等比性质,得
| 1 |
| 2 |
| 2c+2a+2b |
| c+a+b |
当a+b+c=0时,则a+b=-c,
| 1 |
| 2 |
故选D.
点评:熟悉等比性质:若
=
=…=
=k,则
=k,(b+d+…+n≠0).特别注意条件的限制.
| a |
| b |
| c |
| d |
| m |
| n |
| a+c+…+m |
| b+d+…+n |
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