题目内容
| 2 |
| m2-4 |
| 1 |
| 2m-4 |
分析:先把各分母因式分解得到最简公分母为2(m+2)(m-2),然后进行通分得到
,再约分即可.
| 4-(m+2) |
| 2(m+2)(m-2) |
解答:解:原式=
-
=
=
=-
.
| 2 |
| (m+2)(m-2) |
| 1 |
| 2(m-2) |
=
| 4-(m+2) |
| 2(m+2)(m-2) |
=
| -(m-2) |
| 2(m+2)(m-2) |
=-
| 1 |
| 2m+4 |
点评:本题考查了分式的加减法:先把各分母因式分解,确定最简公分母,然后进行通分化为同分母的分式,再把分母不变,分子相加减.
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