题目内容
请根据结合侓,分配侓计算:(
+
+
+…+
)(1+
+
+…+
)-(1+
+
+…+
)(
+
+
+…+
).
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考点:有理数的混合运算
专题:计算题,换元法
分析:可设
+
+
+…+
=x,代数式可以变形为(x+
)(1+x)-(1+x+
)x,再去括号,合并同类项计算即可求解.
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解答:解:设
+
+
+…+
=x,
则(
+
+
+…+
)(1+
+
+…+
)-(1+
+
+…+
)(
+
+
+…+
)
=(x+
)(1+x)-(1+x+
)x
=x2+x+
x+
-x-x2-
x
=
.
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则(
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=(x+
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=x2+x+
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=
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点评:本题考查的是有理数的运算能力,换元法可以简化计算.
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