题目内容
化简并求值:| a2-1 |
| a-1 |
| ||
| a2+a |
| 1 |
| a |
| 2 | ||
1-
|
分析:本题因为所求代数式中有二次根式,故应先确定a的正负,故应先把a化简后再代入原式计算.
解答:解:∵a+1=
+1
=
+1
=-
<0,
∴原式=a+1-
-
=a+1+
-
=a+1=-
.
| 2 | ||
1-
|
=
2(1+
| ||
| 1-3 |
=-
| 3 |
∴原式=a+1-
| ||
| a(a+1) |
| 1 |
| a |
=a+1+
| 1 |
| a |
| 1 |
| a |
=a+1=-
| 3 |
点评:本题考查的是分式的化简求值,在进行此类运算时,若分式中有二次根式,要先确定其正负再化简.
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