题目内容
化简求值:
+
+…+
.
| 1 |
| 1×3 |
| 1 |
| 2×4 |
| 1 |
| 98×100 |
考点:有理数的混合运算
专题:计算题
分析:先提取因数
,原式拆项后,抵消合并即可得到结果.
| 1 |
| 2 |
解答:解:原式=
×(1-
+
-
+
-
…+
-
+
-
+
-
)
=
×(1+
-
-
)
=
×(1+
-
-
)
=
×
=
.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 96 |
| 1 |
| 98 |
| 1 |
| 97 |
| 1 |
| 99 |
| 1 |
| 98 |
| 1 |
| 100 |
=
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 99 |
| 1 |
| 100 |
=
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 99 |
| 1 |
| 100 |
=
| 1 |
| 2 |
| 14651 |
| 9900 |
=
| 14651 |
| 19800 |
点评:考查了有理数的混合运算,解题的关键是将分数进行拆分,通过加减相互抵消,进行简便计算.
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